2.5 g of the carbonate of a metal was treated with 100 mL of 1N H

Subject

Chemistry

Class

NEET Class 12

Test Series

Take Zigya Full and Sectional Test Series. Time it out for real assessment and get your results instantly.

Test Yourself

Practice and master your preparation for a specific topic or chapter. Check you scores at the end of the test.
Advertisement

 Multiple Choice QuestionsMultiple Choice Questions

1.

KF combines with HF to form KHF2. This compound contains the species

  • K+, F- and H+

  • K+, F- and HF

  • K+ and [HF2]-

  • [KHF]+ and F2


2.

pH of a 0.01 M solution (Ka = 6.6 × 10-4)

  • 7.6

  • 8

  • 2.6

  • 5


3.

A vessel of one litre capacity containing 1 mole of SO3 is heated till a state of equilibrium is attained.

2SO3 (g)  2SO2 (g) + O2 (g)

At equilibrium, 0.6 moles of SO2 had formed. The value of equilibrium constant is

  • 0.18

  • 0.36

  • 0.45

  • 0.68


4.

Mercurous chloride exists in the form of

  • Hg+

  • Hg22+

  • Hg2+

  • Hg32+


Advertisement
5.

What is the molarity of H2SO4 solution that has a density of 1.84 g/cc at 35°C and contains 98% by weight?

  • 4.18 M

  • 8.14 M

  • 18.4 M

  • 18 M


6.

The variation of volume V, with temperature T, keeping pressure constant is called the coefficient of thermal expansion (α) of a gas, i.e., α = 1VdVdTP. For an ideal gas α is equal to

  • T

  • 1T

  • P

  • 1P


7.

The molecules having the same hybridization, shape and number of lone pairs of electrons are

  • SeF4, XeO2F2

  • SF4, XeF2

  • XeOF4, TeF4

  • SeCl4, XeF4


Advertisement

8.

2.5 g of the carbonate of a metal was treated with 100 mL of 1N H2SO4. After the completion of the reaction, the solution was boiled off to expel CO2 and was then titrated against 1N NaOH solution. The volume of alkali that would be consumed, if the equivalent weight of the metal is 20

  • 50

  • 25

  • 75

  • 100


A.

50

Equivalent weight of metal carbonate = 20 + 30 = 50

2.5 gm of metal carbonate = 2.550 = 0.05 eq.

Number of equivalent of H2SO4 would have reacted = 0.05

Number of equivalent of H2SO4 taken = 100 × 11000= 0.1

Number of equivalent weight of H2SO4 reamins unreacted = 0.1 - 0.05 = 0.05 eq.

 Number of equivalent of alkali consumed = 0.05 eq.

milli eq = Normality × Volume in mL

1.0 × V = 0.05 × 1000

V = 0.05 × 10001.0 = 50 mL


Advertisement
Advertisement
9.

The equilibrium constant for mutarotation α-D Glucose  β-D Glucose is 1.8. What percentage of α form remains at equilibrium?

  • 35.7

  • 64.3

  • 55.6

  • 44.4


10.

The M - O- M bond angles in MO (where M is halogen) is in the order

  • Br2O > Cl2O > F2O

  • F2O > Br2O > Cl2O

  • F2O > Cl2O > Br2O

  • Cl2O > F2O > Br2O


Advertisement