Which of the following has the highest bond order? from Chemistr

Subject

Chemistry

Class

NEET Class 12

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 Multiple Choice QuestionsMultiple Choice Questions

1.

In the electronic structure of H2SO4 , the total number of unshared electrons is

  • 20

  • 16

  • 12

  • 8


2.

The correct order towards bond angle is

  • sp3 < sp2 < sp

  • sp < sp2 < sp3

  • sp < sp3 < sp2

  • sp2 < sp3 < sp


3.

Which of the following relation is correct ?

  • Ist IE of C > Ist IE of B

  • Ist IE of C < Ist IE of B

  • IInd IE of C > IInd IE of B

  • Both (b) and (c)


4.

Which of the following configurations corresponds to element of highest ionisation energy?

  • 1s2, 2s1

  • 1s2, 2s2, 2p3

  • 1s2, 2s2, 2p2

  • 1s2, 2s2, 2p6, 3s1


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5.

Which of the following has a bond formed by overlap of sp-sp3 hybrid orbitals?

  • CH3 - C  C - H

  • CH3 - CH = CH - CH3

  • CH2 = CH - CH = CH2

  • HC CH


6.

The density of a gas is found to be 1.56 g/L at 745 mm pressure and 65°C. What is the moleculer mass of the gas?

  • 44.2 u

  • 4.42 u

  • 2.24 u

  • 22.4 u


7.

Considering H2O as weak field ligand, the number of unpaired electrons in [Mn(H2O)6] will be (Atomic number of Mn = 25)

  • five

  • two

  • four

  • three


8.

The quantum numbers +12 and -12 for the electron spin represent

  • rotation of the electron in clockwise and anticlockwise direction respectively

  • rotation of the electron in anticlockwise and clockwise direction respectively

  • magnetic moment of the electron pointing up and down respectively

  • two quantum mechanical spin states which have no classical analogues


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9.

Which of the following has the highest bond order?

  • N2

  • O2

  • He2

  • H2


A.

N2

N2( 7 + 7 = 14e-) = KK*σ2s2σ*2s2π2px2

                            π2py2 , σ2pz2

                   BO    = 12(8 - 2) = 3

O(8 + 8 =16e-) = KK*σ2s2σ*2s2σ2pz2

                             π2px2  π2py2 , π* 2px1  π* 2py1

                   BO   = 12 (8 - 4) = 2

He( 2 + 2 = 4e-) = σ1s2σ*1s2

                       BO = 12(2 - 2) = 0

H2 (1 + 1 = 2e-) = σ1s2

                  BO   = 12(2 - 0) = 1

Hence, N2 has the highest bond order.


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10.

In long form of Periodic Table, the properties of the elements are a periodic function of their

  • atomic size

  • ionisation energy

  • atomic mass

  • atomic number


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