Which of the following orders regarding ionisation energy is corr

Subject

Chemistry

Class

NEET Class 12

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 Multiple Choice QuestionsMultiple Choice Questions

11.

In Periodic Table, the basic character of oxides

  • increases from left to right and decreases from top to bottom

  • decreases from right to left and increases from top to bottom

  • decreases from left to right and increases from top to bottom

  • decreases from left to right and increases from bottom to top


12.

Which one of the following contains P-O-P bond?

  • Hypophosphorus acid

  • Phosphorus acid

  • Pyrophosphoric acid

  • Orthophosphoric acid


13.

Which of the following orbitals will have zero probability  of finding the electron in the yplane. 

  • px

  • py

  • pz

  • dyz


14.

What type of orbital hybridisation is considered on P in PCl5?

  • sp3d

  • dsp3

  • sp3d2

  • d2sp3


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15.

In haemoglobin, the metal ion present is

  • Fe2+

  • Zn2+

  • Co2+

  • Cu2+


16.

The bond order of CO molecule is

  • 2

  • 2.5

  • 3

  • 3.5


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17.

Which of the following orders regarding ionisation energy is correct?

  • N > O > F

  • N < O < F

  • N > O < F

  • N < O < F


C.

N > O < F

Ionisation energy is the energy required to remove an electron from outer shell of an atom. Since, on moving from left to right in a period, size decreases, thus, larger amount of energy is required to remove an electron, i.e. ionisation energy increases.

The size of Oxygen atom is smaller as compared to Nitrogen but the ionisation energy of Nitrogen is higher. This is mainly because in Nitrogen, the electron is to be removed from half-filled 2p3 orbital.

Thus, the correct order of ionisation energy is O < N < F.


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18.

Which of the following compounds shows evidence of the strongest hydrogen bonding?

  • Propan-1-ol

  • Propan-2-ol

  • Propan-1,2-diol

  • Propan-1,2,3-triol


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19.

Identify [A] and [B] in the following

Ac89227 -β [A] -α [B] -α Rn

  • Po, Rn

  • Th, Po

  • Ra, Th

  • Th, Ra


20.

A weak acid of dissociation constant 10-5 is being titrated with aqueous NaOH solution. The pH at the point of one-third neutralisation of the acid will be

  • 5 + log 2 - log 3

  • 5 - log 2

  • 5 - log 3

  • 5 - log 6


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