The compressibility of a gas is less than unity at STP, therefore,
Vm > 22.4 L
Vm < 22.4 L
Vm = 22.4
Vm = 44.8 L
Among the following set of quantum numbers, the impossible set is
n | l | m | s |
3 | 2 | -3 | -1/2 |
n | l | m | s |
4 | 0 | 0 | 1/2 |
n | l | m | s |
5 | 3 | 0 | -1/2 |
n | l | m | s |
3 | 2 | -2 | 1/2 |
Among the following compounds, which compound is polar as well as exhibit sp2-hybridisation by the central atom.
H2CO3
SiF4
BF4
HClO3
The energy released when 6 moles of octane is burnt in air will be [Given, ΔHf for CO2 (g). H2O(g) and C8H18 (l), respectively are -490, -240 and +160J/mol]
-37.4 kJ
-20 kJ
-6.2 kJ
-35.5 kJ
When 750 mL of 0.5 M HCl is mixed with 250 mL of 2 M NaOH solution, the value of pH will be
pH = 7
pH > 7
pH < 7
pH = 0
Match the type of series given in Column I with the wavelength range given in Column II and choose the correct option.
Column I | Column II | ||
A | Lyman | 1. | Ultraviolet |
B. | Paschen | 2. | Near-infrared |
C. | Balmer | 3. | Far Infrared |
D. | Pfund | 4. | Visible |
A | B | C | D |
1 | 2 | 4 | 3 |
A | B | C | D |
4 | 3 | 1 | 2 |
A | B | C | D |
3 | 1 | 2 | 4 |
A | B | C | D |
4 | 3 | 2 | 1 |
The electrons identified by quantum numbers n and l, are as follows
n = 4, l = 0
n =3, l= 2
If we arrange them in order of increasing energy, i.e., from lowest to highest, the correct order is
IV<II<III<I
II<IV<I<III
I < III < II < IV
III < I < IV < II
Which of the following is the correct order of stability for the given superoxides?
KO2 < RbO2 < CsO2
CsO2 < RbO2<KO2
RbO2
KO2 < CsO2 <RbO2
A.
KO2 < RbO2 < CsO2
With a progressive increase in the size of alkali metal ions, the stability of superoxides increases because the size of superoxide ion is large and large cation can be stabilised more by large anion.
Therefore, the order of stability is
KO2 <RbO2 < CsO2