The compressibility of a gas is less than unity at STP, therefore,
Vm > 22.4 L
Vm < 22.4 L
Vm = 22.4
Vm = 44.8 L
Among the following set of quantum numbers, the impossible set is
n | l | m | s |
3 | 2 | -3 | -1/2 |
n | l | m | s |
4 | 0 | 0 | 1/2 |
n | l | m | s |
5 | 3 | 0 | -1/2 |
n | l | m | s |
3 | 2 | -2 | 1/2 |
Among the following compounds, which compound is polar as well as exhibit sp2-hybridisation by the central atom.
H2CO3
SiF4
BF4
HClO3
The energy released when 6 moles of octane is burnt in air will be [Given, ΔHf for CO2 (g). H2O(g) and C8H18 (l), respectively are -490, -240 and +160J/mol]
-37.4 kJ
-20 kJ
-6.2 kJ
-35.5 kJ
When 750 mL of 0.5 M HCl is mixed with 250 mL of 2 M NaOH solution, the value of pH will be
pH = 7
pH > 7
pH < 7
pH = 0
Match the type of series given in Column I with the wavelength range given in Column II and choose the correct option.
Column I | Column II | ||
A | Lyman | 1. | Ultraviolet |
B. | Paschen | 2. | Near-infrared |
C. | Balmer | 3. | Far Infrared |
D. | Pfund | 4. | Visible |
A | B | C | D |
1 | 2 | 4 | 3 |
A | B | C | D |
4 | 3 | 1 | 2 |
A | B | C | D |
3 | 1 | 2 | 4 |
A | B | C | D |
4 | 3 | 2 | 1 |
The electrons identified by quantum numbers n and l, are as follows
n = 4, l = 0
n =3, l= 2
If we arrange them in order of increasing energy, i.e., from lowest to highest, the correct order is
IV<II<III<I
II<IV<I<III
I < III < II < IV
III < I < IV < II
A.
IV<II<III<I
Reason:
(i) More be the sum of n + l → more be the energy.
(ii) For the
same sum, the more value of n, have higher energy.
Because, n + l for →
(a) 4 + 1 = 5
(b) 4 + 0 = 4
(c) 3+ 2 = 5
(d) 3+1 = 4
therefore, correct order is (iv)<(ii) < (iii) < (i)
Which of the following is the correct order of stability for the given superoxides?
KO2 < RbO2 < CsO2
CsO2 < RbO2<KO2
RbO2
KO2 < CsO2 <RbO2