Three different objects m1 , m2 and m3 to fall from rest and from the same point O along three different frictionless paths. The speeds of the three objects, on reaching the ground, will be in the ratio of
m1 : m2 : m3
1 : 1 : 1
m1 : 2 m2 : 3m3
A particle starts from rest and has an acceleration of 2 m/s2 for 10 sec. After that, it travels for 30 sec with constant speed and then undergoes a retardation of 4 m/s2 and comes back to rest. The total distance covered by the particle is
650 m
750 m
700 m
800 m
B.
750 m
Initial velocity ( u ) = 0
Acceleration ( ) = 2 m/s2
time during acceleration (t1) = 10 sec
Time during constant velocity (t2 ) = 30 sec
and retardation ( ) = 4 m/s2
( negative sign due to retardation )
Distance covered by the particle during acceleration
s1 = ut1 +
= ( 0 × 10 ) + × 2 × (10)2
s1 = 100 m ......(i)
And velocity of the particle a the end of acceleration
v = u +
= 0 + ( 2 × 10 )
v = 20 m/s
Therefore distance covered by the particle during constant velocity
s2 = v × t2
= 20 × 30⇒
s2 = 600 m .....(ii)
Relation for the distance covered by the particle during retardation ( s3 ) is
v2 = u2 + 2s3
⇒ ( 0 )2 = ( 20 )2 + 2 × ( 4 ) × s3
⇒ 400 = 8 s3
⇒ s3 =
⇒ s3 = 50 m
Therefore total distance covered by the particle
s = s1 + s2 + s3
= 100 +600 + 50
s = 750 m
At the uppermost point of a projectile, its velocity and acceleration are at an angle of
0°
90°
45°
180°
The kinetic energy of a body becomes four times its initial value. The new linear momentum will be
same as the initial value
four times the initial value
twice of the initial value
eight times of the initial value
The angular momentum of a moving body remains constant if
net external force is applied
net external torque is applied
net pressure is applied
net external torque is not applied
Kepler's second law is based on
Newton's first law
special theory of relativity
Newton's second law
Conservation of angular momentum