An explosion blows a rock into three parts. Two parts go off at

Subject

Physics

Class

NEET Class 12

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 Multiple Choice QuestionsMultiple Choice Questions

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1.

An explosion blows a rock into three parts. Two parts go off at right angles to each other. These two are 1 kg first part moving with a velocity of 12 ms-1 and 2 kg second part moving with a velocity of 8 ms-1.If the third part flies off with a velocity of 4 ms-,its mass would be

  • 5 kg 

  • 7 kg

  • 17 kg

  • 17 kg


A.

5 kg 

apply the law of conservation of linear momentum. 

momentum of first part = 1 x 12 = 12 kg ms-1
Momentum of the second part  = 2 x 8 = 16 kg ms-1 '

Resultant monmentum

= [(12)2 +(16)2]1/2 = 20 kg ms-1

The third part should also have the same momentum.


Let the mass of third part be M, then 

4 x M = 20

M = 5 kg
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2.

If the dimensions of a physical quantity are given by Ma Lb Tc, the physical quantity will be 

  • pressure if a = 1, b = -1, c= 2

  • velocity if a = 1, b = 1, c = -2

  • acceleration if a = 1, b = 1, c =-2

  • acceleration if a = 1, b = 1, c =-2

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3.

Under the influence of a uniform magnetic field, a charged particle moves with constant speed v in a circle of radius R. The time period of rotation of the particle

  • depends on v and not on R

  • depends on R and not on v

  • is independent of both v and R

  • is independent of both v and R

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4.

A body mass 1 kg is thrown upwards with velocity 20 ms-1. It momentarily comes to rest after attaining a height of 18 m. How much energy is lost due to air friction?  (g = 10 ms-2)

  • 20 J

  • 30 J

  • 40 J

  • 40 J

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5.

The mass of a lift is 2000 kg. When the tension in the supporting cable is 28000 N, then its acceleration is 

  • 30 ms-2 downward

  • 4 ms-2  upwards

  •  4 ms-2  downwards

  •  4 ms-2  downwards

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6.

A particle starts its motion from rest under the action of a constant force. If the distance covered in first 10 s is s1 and that covered in the first 20 s is s2, then

  • s2 = 2s1

  • s2 = 3s1

  • s2 = 4 s1

  • s2 = 4 s1

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7.

A thin circular ring of mass M and radius R is rotating in a horizontal plane about an axis vertical to its plane with a constant angular velocity ω. If two objects each of mass m be attached gently to the opposite ends of a diameter of the ring. the ring will then rotate with an angular velocity

  • fraction numerator straight omega space left parenthesis straight M space minus 2 straight m right parenthesis over denominator straight M space plus space 2 straight m end fraction
  • fraction numerator ωM over denominator straight M space plus space 2 straight m end fraction
  • fraction numerator straight omega left parenthesis straight M space plus 2 straight m right parenthesis over denominator straight M end fraction
  • fraction numerator straight omega left parenthesis straight M space plus 2 straight m right parenthesis over denominator straight M end fraction
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8.

Two bodies of mass 1 kg have position vectors,bold i with bold hat on top bold space bold plus bold space 2 bold j with bold hat on top bold space bold plus bold k with bold hat on top bold space bold and bold space bold minus 3 bold i with bold hat on top bold space bold minus 2 bold j with bold hat on top bold space bold plus bold k with bold hat on top  respectively.The centre of mass of this system has a position vector

  • negative 2 bold i with hat on top space plus 2 space bold k with hat on top
  • negative 2 bold i with bold hat on top minus bold j with bold hat on top space plus bold k with hat on top
  • 2 bold i with bold hat on top minus bold j with bold hat on top space minus bold k with hat on top
  • 2 bold i with bold hat on top minus bold j with bold hat on top space minus bold k with hat on top
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9.

Four identical thin rods each of mass M and length l , inertial form a square frame. moment of inertia of this frame about an axis through the centre of the square and perpendicular to this plane is 

  • 4Ml2/3

  • 2Ml2/3

  • 13Ml2/3

  • 13Ml2/3

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10.

The figure shows elliptical orbit of a planet m about the sun S. The shaded are SCD is twice the shaded area SAB. If t1 is the time for the planet to move from C to D and t2 is the time to move from A to B then,

  • t1 > t2

  • t1 =4 t2

  • t1 = 2t2

  • t1 = 2t2

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