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NEET Physics Solved Question Paper 2009

Multiple Choice Questions

$\vec{A} and \vec{B}$ are two vectors given by $\vec{A} = 2 \hat{i} + 3 \hat{j}$ and $\vec{B} = \hat{i} + \hat{j}$ . The magnitude of the component of $\vec{A}$ along $\vec{B}$ is

$\frac{5}{\sqrt{2}}$
$\frac{3}{\sqrt{2}}$
$\frac{7}{\sqrt{2}}$
$\frac{1}{\sqrt{2}}$

Given $\vec{C} = \vec{A} \times \vec{B} and \vec{D} = \vec{B} \times \vec{A}$ . What is the angle between $\vec{C} and \vec{D}$ ?

30°
60°
90°
180°

The acceleration a (in ms^-2 ) of a body, starting from rest varies with time t (in s) following the equation a = 3 t + 4. The velocity of the body at time t = 2 s will be

10 ms^-1
18 ms^-1
14 ms^-1
26 ms^-1

Figure below shows the distance-time graph of the motion of a car. It follows from the graph that the car is

at rest
in uniform motion
in non-uniform acceleration
uniformly accelerated

5.
Two particles have masses m and 4m and their kinetic energies are in the ratio 2 : 1. What is the ratio of their linear momenta ?

$\frac{1}{\sqrt{2}}$

$\frac{1}{2}$

$\frac{1}{4}$

$\frac{1}{16}$

$\frac{1}{\sqrt{2}}$

$As, KE = \frac{p^{2}}{2 m} ∴ \frac{{p_{1}}^{2}}{{p_{2}}^{2}} = \frac{m_{1}}{m_{2}} . \frac{{KE}_{1}}{{KE}_{2}} = \frac{1}{4} . \frac{2}{1} = \frac{1}{2} \Rightarrow \frac{p_{1}}{p_{2}} = \frac{1}{\sqrt{2}}$

The force F acting on a particle moving in a straight line is shown below. What is the work done by the force on the particle in the 1st metre of the trajectory ?

5 J
10 J
15 J
2.5 J

If the kinetic energy of a body changes by 20 %, then its momentum would change by

20 %
24 %
9.5 %
44 %

A bullet is fired with a velocity u making an angle of 60° with the horizontal plane. The horizontal component of the velocity of the bullet when it reaches the maximum height is