A ball is released from certain height which losses 50% of its kinetic energy on striking the ground it will contain a height again
of initial height
of initial height
th of initial height
None of the above
If applied torque on a system is zero, i.e.,Τ = 0 , then for that system
ω = 0
α = 0
J = 0
F = 0
B.
α = 0
τ the torque on a given axis is product of moment of inertia and angular acceleration.
I = moment of inertia
α = angular acceleration
If
But I ≠ 0
α = 0
When the torque acting upon a system is zero, the angular momentum is constant and hence conserved. This is analogous to the linear counterpart i.e when the force on the system is zero, the momentum is conserved.
A particle moves towards east for 2 s with velocity 15 m/s and move towards north for 8 s with velocity 5 m/s. Then, average velocity of the particle is
1 m/s
5 m/s
7 m/s
10 m/s
Match the following
Angular momentum | 1. [M-1 L2 T-2 ] |
B. Torque | 2 [M1 L2 T-2 |
C. Gravitational constant | 3.[M1 L2 T-2] |
D. Tension | 4.[M1 L2 T-1] |
C- 2, D - 1
A - 4, B - 3
A - 3, C -2
B-2, A - 1
If we increase kinetic energy of a body 300%, then per cent increase in its momentum is
50%
300%
100%
150%
Change in acceleration due to gravity is same upto a height h from each other the earth surface and below depth x then relation between x and his ( h and x<<<Re )
x = h
x = 2h
x =
x = h2
Three points charges +q, -2q and +q are placed at points (x=0, y=a, z=0), ( x=0, y=0, z=0 ) and (x=a, y=0, z=0), respectively. The magnitude and direction of the electric dipole moment vector of this charge assembly are
√2 qa along + y direction
√2 qa along the line joining point
qa along the line joining points (x = 0,y = 0, z = 0) and (x = a, y = a, z = 0)
√2 qa along + x direction
A block B is pushed momentarily along a horizontal surface with an initial velocity v. If is the coefficient of vlicling friction between B and the surface, block B will come to rest after a time
A particle of mass M and charge Q moving with velocity v describes a circular path of radius R when subjected to a uniform transverse magnetic field of induction B. The work done by the field, when the particle completes one full circle, is
zero
A particle of mass 100 g is thrown vertically upward with a speed of 5 m/s. The work done by the force of gravity during the time the particle goes up is
-0.5 J
-1.25 J
1.25 J
0.5 J