If the units of length, mass and force are chosen as fundamental units, the dimensions of time would be
[ M1/2 L-1/2 F1/2 ]
[ M1/2 L1/2 F1/2 ]
[ M1/2 L1/2 F-1/2 ]
[ M1/2 L-1/2 F-1/2 ]
A block of mass 2 kg is placed on the floor. The coefficient of static friction is . If a force of N is applied on the block parallel to the floor, the force of friction between the block and the floor is (g = 10 ms-2 )
N
2 N
8 N
Zero
A heavy truck moving with a velocity of 60 km h-1 collides with a light drum at rest. If the collision be elastic, then the velocity of the drum immediately after collision will be
zero
60 km h-1
120 km h-1
uncertain
A cyclist is moving in a circular track of radius 80 m with a velocity of 36 km h-1. He has to lean from the vertical approximately through an angle (Take g = 10 m s-2 )
tan-1 (4)
tan-1(1/8)
tan-1(1/4)
tan-1(2)
A satellite is in an orbit around the earth. If its kinetic energy is doubled, then
it will maintain its path
it will fall on the earth
it will rotate with a great speed
it will escape out of earth's gravitational field
A steel wire with cross-section 3 cm2 has elastic limit 2.4 x 108 N m-2. The maximum upward acceleration that can be given to a 1200 kg elevator supported by this cable wire if the stress is not to exceed one-third of the elastic limit is (Take g = 10 ms-2)
12 m s-2
10 m s-2
8 m s-2
7 m s-2
An arrow is projected into air. Its time of flight is 5 s and range 200 m. What is the maximum height reached by it? ( Take g= 10 ms-2 )
31·25 m
24·5 m
18·25 m
46·75 m
A particle moves in a circular path with decreasing speed. Choose the correct statement.
Angular momentum remains constant
Acceleration is towards the centre
Particle moves in a spiral path with decreasing radius
The direction of angular momentum remains constant
A body of mass 2 kg is thrown up vertically with kinetic energy of 490 J. The height at which the kinetic energy of the body becomes half of its original value is
50 m
12.25 m
25 m
10 m
Two homogeneous spheres A and B of masses m and 2m having radii 2a and a respectively are placed in touch. The distance of centre of mass from first sphere is
a
2a
3a
none of these
B.
2a
Given:-
m1 = m
m2 = 2 m
Centre of mass given by,
∴ XCM =
x1 - distance of particle from origin
x2 - distance of second particle from origin
For example
x1 = 0 cm
x2 = 3 cm
XCM =
=
XCM = 2a