If  then the value of  will be from Quantitative Aptitude S

Subject

Quantitative Aptitude

Class

SSCCGL Class 12

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 Multiple Choice QuestionsMultiple Choice Questions

1.

A General, while arranging his men, who were 6000 in number, in the form of a square, found that there were 71 men left over. How many were arranged in each row?

  • 73

  • 77

  • 87

  • 87

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2.

A number, when divided successively by 4, 5 and 6 leaves remainders 2, 3 and 4 respectively. The least such number is

  • 50

  • 53

  • 56

  • 58

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3.

A number, when divided by 296, gives 75 as the remainder. If the same number is divided by 37 then the remainder will be

  • 1

  • 2

  • 19

  • 19

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4.

The square root of
fraction numerator left parenthesis 0.75 right parenthesis cubed over denominator 1 minus 0.75 end fraction space plus space open square brackets 0.75 space plus space left parenthesis 0.75 right parenthesis squared space plus space 1 close square brackets is

  • 1

  • 2

  • 3

  • 3

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5.

The sum and product of two numbers are 12 and 35 respectively. The sum of their reciprocals will be

  • 1 third
  • 1 fifth
  • 12 over 35
  • 12 over 35
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6.

If straight a squared space plus space straight b squared space plus space 1 over straight a squared space plus space 1 over straight b squared space equals space 4 comma then the value of straight a squared space plus space straight b squared will be

  • 1

  • 1 1 half
  • 2

  • 2


C.

2

Shortcut Method:
Put a = 1,  b = 1 , as it balances the equation.
rightwards double arrow space space space space straight a squared space plus straight b squared space plus space 1 over straight a squared space plus 1 over straight b squared space equals space 4
rightwards double arrow space space space 1 squared space plus space 1 squared space plus space 1 over 1 squared space plus space 1 over 1 squared space equals space 4
∴ the value of a2 + b2 is open square brackets left parenthesis 1 right parenthesis squared space plus space left parenthesis 1 right parenthesis squared space equals space 2 close square brackets

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7.

If open parentheses straight x plus 1 over straight x close parentheses squared space equals space 3, then open parentheses straight x cubed space plus space 1 over straight x cubed close parentheses is equal to

  • 3

  • 2

  • 1

  • 1

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8. fraction numerator 0.1 space cross times space 0.1 space cross times space 0.1 space plus space 0.02 space cross times space 0.02 space cross times space 0.02 over denominator 0.2 space cross times space 0.2 space cross times space 0.2 space plus space 0.04 space cross times space 0.04 space cross times space 0.04 end fraction is equal to
  • 0.125

  • 0.250

  • 0.500

  • 0.500

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9.

If straight x plus 1 over straight x space equals space 2, then the value of straight x to the power of 100 space plus space 1 over straight x to the power of 100 is

  • 2

  • 0

  • 1

  • 1

129 Views

10.

If straight x cubed plus 3 straight x squared plus 3 straight x space equals space 7 comma then x is equal to

  • 2

  • cube root of 6
  • 1

  • 1

165 Views

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