If  then the value of  is: from Quantitative

Subject

Quantitative Aptitude

Class

SSCCGL Class 12

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 Multiple Choice QuestionsMultiple Choice Questions

51.

Number of composite numbers lying between 67 and 101 is

  • 27

  • 24

  • 26

  • 23

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52.

A dealer allows a discount of 15%. A customer pays an amount of Rs 318.75 for an article. At what price is the article listed?

  • Rs 366.50

  • Rs 375.00

  • Rs 350.00

  • Rs 431.25

67 Views

53.

The reciprocals of the squares of the numbers 1 1 half space and space 1 1 third are in the ratio:

  • 64 : 81

  • 8 : 9

  • 81 : 64

  • 9 : 8

59 Views

54.

The average of 15 numbers is 7. If the average of the first 8 numbers is 6.5 and the average of the last 8 number is 8.5. then middle number is

  • 10

  • 23

  • 13

  • 15

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55.

A man bought 25 creates of oranges for Rs 10,000/-. He lost 5 crates. In order to earn a total profit of 25% of the total cost, he would have to sell each of the remaining crates at:

  • Rs 650/-

  • Rs 625/-

  • Rs 600/-

  • Rs 575/-

94 Views

56.

What is the difference between 0.6 and 0.6%?

  • 5.94

  • 0.594

  • 60

  • 54

55 Views

57.

A man travells 3 over 4 th of the distance of his journey by bus, 1 over 6 th by Rickshaw and 2 km on foot. The total distance travelled by the man is

  • 12 km

  • 18 km

  • 20 km

  • 24 km

55 Views

58.

The compound interest on Rs 1,000/- at 10% per annum for 3 years (in Rs) is:

  • Rs. 1,331/-

  • Rs. 331/-

  • Rs. 300/-

  • Rs. 1,300/-

45 Views

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59.

If square root of 3 space equals space 1.732 comma space then the value of fraction numerator 9 plus 2 square root of 3 over denominator square root of 3 end fraction is:

  • 7.169

  • 7.196

  • 5.198

  • 7.296

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60.

If straight x space plus space 1 over straight x space equals space 2 comma then the value of straight x to the power of 99 space plus space 1 over straight x to the power of 99 minus 2 is:

  • -2

  • 0

  • 2

  • 4


B.

0

straight x space plus space 1 over straight x space equals space 2,
Put the value of x = 1 as it satisfies the equation,
1 plus 1 over 1 space equals space 2 
therefore space space space space space straight x to the power of 99 space plus space 1 over straight x to the power of 99 space minus space 2 space equals space left parenthesis 1 right parenthesis to the power of 99 space plus space fraction numerator 1 over denominator left parenthesis 1 right parenthesis to the power of 99 end fraction minus 2 space equals space 2 space space minus space 2 space equals space 0

 

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