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SSCCGL Quantitative Aptitude Solved Question Paper 2017

Multiple Choice Questions

51.

What is the remainder when 6910 is divided by 81?

53.

Area of 4 walls of a cuboid is 57m², if its length is 5.5 m and height is 3 m. What is the breadth (in m)?

4.5 m
4 m
3 m
3.5 m

54.

At 30% discount the selling price of an article is ₹ 1,050/-. What is the selling price (in ₹) if the discount is 15%?

₹ 1,200/-
₹ 1,175/-
₹ 1,100/-
₹ 1,275/-

55.

What is the fourth proportional to 336, 288 and 161?

60.

The simple and compound interest that can be earned in two years at the same rate is ₹ 4,000/- and ₹ 4,180/- respectively. What is the rate(% per annum) of interest?

18% per annum
4.5% per annum
9% per annum
12% per annum

61.

If $fraction numerator 2 straight x over denominator 3 end fraction minus fraction numerator open square brackets 5 open parentheses begin display style fraction numerator 4 straight x over denominator 5 end fraction end style minus begin display style 4 over 3 end style close parentheses close square brackets over denominator 2 end fraction space equals space 1 third comma$ then what is the value of x?

$9 over 4$
$4 over 9$
$negative 9 over 4$
$negative 4 over 9$

63.

6 times a fraction is greater than 7 times its reciprocal by 11. What is the fraction?

$5 over 3$
$7 over 3$
$5 over 4$
$4 over 5$

73.
A watch having marked price as ₹ 8,400/- is sold for ₹ 5,040/- after two successive discounts. If the first discount is 25%, then what is the second discount percentage?

0.15%

20%

0.25%

0.3%

20%

Let the second discount be x%
Now, According to the question,
$\Rightarrow 8400 \times \frac{(100 - 25)}{100} \times \frac{(100 - x)}{100} = 5040 \Rightarrow 84 \times 75 \times \frac{(100 - x)}{100} = 5040 \Rightarrow 21 \times 3 \times (100 - x) = 5040$
$\Rightarrow 6300 - 63 x = 5040 \Rightarrow 63 x = 6300 - 5040 \Rightarrow 63 x = 1260 \Rightarrow x = 20 %$