Vertices of quadrilateral ABCD are on circumference of a circle. If AB is diameter of circle and $\angle$ADC = 130°, then $\angle$BAC is

• 50⁰

• 40⁰

• 30⁰

• 20⁰

OA, OB and OC are edges of a cube meeting at vertex O. If length of each is a cm, then area of $∆$ABC will be

• a² cm²

• $\frac{\sqrt{3}}{4}{\mathrm{a}}^2 {\mathrm{cm}}^2$

• $\frac{\sqrt{3}}{2}{\mathrm{a}}^2 {\mathrm{cm}}^2$

• $\frac{3}{4}\mathrm{a} {\mathrm{cm}}^2$

13.

Two cylinders have equal volumes and their heights are in the ratio 1: 3. The ratio of their radii will be

• 1 : 3

• 3 : 1

• $\sqrt{3} :\hspace{0.17em}3$

• $3 : \sqrt{3}$

Area of two similar triangles are 4 cm² and 9 cm² respectively. The ratio of their corresponding sides is

• 4 : 9

• 9 : 4

• 3 : 2

• 2 : 3

$$\begin{gathered} \mathrm{If} \mathrm{a}, \mathrm{b} \mathrm{and} \mathrm{c} \mathrm{are} \mathrm{any} \mathrm{three} \mathrm{non}-\mathrm{zero} \mathrm{real} \mathrm{numbers} \mathrm{and}, \frac{\mathrm{a}}{2} = \frac{\mathrm{b}}{3} = \frac{\mathrm{c}}{4} = \frac{2\mathrm{a} - 3\mathrm{b} + 5\mathrm{c}}{\mathrm{A}}, \\ \mathrm{then} \mathrm{the} \mathrm{value} \mathrm{of} \mathrm{A} \mathrm{is} \end{gathered}$$

• 7

• 9

• 11

• 15

$\mathrm{If} {\mathrm{a}}^{\mathrm{x}} = \mathrm{b}, {\mathrm{b}}^{\mathrm{y}} = \mathrm{c} \mathrm{and} {\mathrm{c}}^{\mathrm{z}} = \mathrm{a}, \mathrm{then} \mathrm{the} \mathrm{non}-\mathrm{zero} \mathrm{value} \mathrm{of} \left(\mathrm{xyz}\right) \mathrm{is}$

• 1

• 2

• 3

• - 1

$$\begin{gathered} \mathrm{If} \frac{1}{\mathrm{x}} + \frac{1}{\mathrm{y}} = \mathrm{u} \mathrm{and} \mathrm{xy} = \frac{1}{\mathrm{v}}, \mathrm{then} \mathrm{the} \mathrm{value} \mathrm{of} \\ \frac{1}{{\mathrm{x}}^2} + \frac{1}{{\mathrm{y}}^2} \mathrm{is} \end{gathered}$$

• $\frac{1}{{\mathrm{\mu }}^2} - \frac{2}{\mathrm{\nu }}$

• ${\mathrm{\mu }}^2 - \frac{2}{\mathrm{\nu }}$

• ${\mathrm{\mu }}^2 - 2\mathrm{\nu }$

• $\frac{1}{{\mathrm{\mu }}^2} - 2\mathrm{\nu }$

$\mathrm{The} \mathrm{value} \mathrm{of}, \mathrm{x} \mathrm{if} 5^{\mathrm{x}}{\left(\sqrt{32}\right)}^{\frac{\mathrm{x}}{\mathrm{x} + 3}} = 50 \mathrm{is}$

• - 1

• 1

• 2

• 3

Salman solve - 3 - 4 = 7. The error is committed as

• Salman needs to practice solving problems of similar type

• Salman has not understood the concept of multiplication of integers

• Salman is careless

• Salman is not clear about the concept of addition of integer