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Construct a triangle ABC in which AB = 5 cm, ∠B = 60° and altitude CD = 3 cm. Construct a triangle AQR similar to ΔABC, such that each side of ΔAQR is 1.5 times that of the corresponding side of ΔABC.



Steps of Construction :
(i)    Draw a line segment AB = 5 cm.(ii)

Steps of Construction :

(i)    Draw a line segment AB = 5 cm.
(ii)    Draw ∠ABX = 60°.
(iii)    Draw AM ⊥ AB at A.
(iv)    Draw NT ⊥ AM cutting BX at C.
(v)    Join AC.
Now, ABC is the required triangle.
Construction of another triangle AQR similar to ΔABC.
Steps of Construction :
(i) Produce AB to Q such that

AQ equals 3 over 2 cross times AB space equals 3 over 2 cross times 5 space equals space 7.5 space cm.

(ii)    Draw ∠SQA = 60°.
(iii)    Produce AC to cut QS at R.
Then ΔAQR is the required triangle.

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