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A conical flask is full of mater. The flask was base m radius r and height n. the mater is poored into a cylindrical flask of base radius mr. find the height of water in the cylindrical flask.


Here, we have base radius of conical flask = r and height = h
Then,
Volume of conical flask = 1 third space πr squared straight h
Again,
Base radius of cylindrical flask = mr.
Let height of cylindrical flask = h
Then, volume = π (mr)2h1
Now,
Volume of Conical flask
= volume of cylindrical flask

rightwards double arrow space space space space 1 third πr squared straight h space equals space straight pi space left parenthesis mr right parenthesis squared straight h subscript 1
rightwards double arrow space space space space space straight h subscript 1 equals fraction numerator straight r squared straight h over denominator 3 straight m squared straight r squared end fraction equals fraction numerator straight h over denominator 3 straight m squared end fraction

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