Minimum and maximum z = 5x + 2y subject to the following constraints:
x – 2y ≤ 2
3x + 2y ≤ 12
−3x + 2y ≤ 3
x ≥ 0, y ≥ 0
Point (x,y) | Values of the objective function Z= 5x+2y |
A(0, 5) | 5 × 0 + 2 × 5 = 10 |
B(3.5, 0.75) | 5 x 3.5 +2 x 0.75 =19 (Maximum) |
C(2, 0) | 5 x 1.5 +2 x 3.75 =15 |
O(0,0) | 5 x 0 + 2 x 0 = 0 (Minimum) |