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From the given equation

$2 space sin space straight y space cos space straight y. space dy over dx minus space sin space xy. space open square brackets straight x. dy over dx plus straight y.1 close square brackets space equals 0 rightwards double arrow space dy over dx space equals space fraction numerator straight y space sin space xy over denominator sin space 2 straight y space minus space straight x space sin left parenthesis space xy right parenthesis end fraction therefore space right enclose dy over dx end enclose subscript straight x space equals 1 comma space straight y space equals straight pi over 4 end subscript space equals space fraction numerator straight pi over denominator 4 left parenthesis square root of 2 minus 1 right parenthesis end fraction$

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Inverse Trigonometric Functions

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