Calculate resistance in the following combination of resistances.

We are given three 6 Ω resistors connected in parallel with each other and one 3 Ω resistance.

Equivalent resistance of 6 Ω resistors connected in parallel is given by,

\frac{1}{R_{p}} = \frac{1}{6} + \frac{1}{6} + \frac{1}{6} = \frac{3}{6} = \frac{1}{2} \Rightarrow R_{p} = 2 Ω

Now, Resistors 3 Ω and 2 Ω are in series.

Therefore,
Net resistance, R = 3 + 2 = 5 Ω, is the required resistance of the combination.

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