Draw the graph to show variation of binding energy per nucleon with mass number of different atomic nuclei. Calculate binding energy/nucleon of ${}_{20}^{40}{Ca}$ nucleus.
Given:
mass of ${}_{20}^{40}{Ca} = 39.962589 u$
mass of proton = 1.007825 u
mass of neutron = 1.008665 u
and 1 u = 931 MeV/c^2.

The graph showing the variation of binding energy per nucleon with mass number of atomic nuclei is shown on below.

Numerical:

straight Q space equals space left square bracket 20 space straight m subscript straight n space plus space 20 space straight m subscript straight p space minus space straight m left parenthesis Ca right parenthesis right square bracket space straight c squared

equals space left parenthesis 20 cross times 1.008665 plus 20 cross times 1.007825 minus 39.962589 right parenthesis space straight c squared

equals space 0.367211 space straight u space cross times space fraction numerator 931.5 over denominator straight u end fraction space MeV equals space 342 space MeV

Hence, the B.E. per nucleon of

Ca presubscript 20 presuperscript 40

nucleus

equals space straight Q over straight A space equals space 342 over 40 space equals space 8.55 space MeV divided by nucleon.

1222 Views

Nuclei

Hope you found this question and answer to be good. Find many more questions on Nuclei with answers for your assignments and practice.

Browse through more topics from Physics Part II for questions and snapshot.