From the following bond energies:
H-H bond energy: 431.37 kJ mol-
C=C bond energy: 606.10 kJ mol-
C- C bond energy: 336.49 kJ mol-
C-H bond energy: 410.50 kJ mol-
Enthalpy for the reaction,
will be
1523.6 kJ mol-
-243.6 kJ mol-
-1200. kJ mol-
-1200. kJ mol-
According to MO theory which of the following lists ranks the nitrogen species in terms of increasing bond order?
The state of hybridization of C2, C3, C5 and C6 of the hydrocarbon,
is in the following sequence
sp, sp3, sp2 and sp3
sp3, sp2, sp2 and sp
sp,sp2,sp2 and sp3
sp,sp2,sp2 and sp3
In which of the following molecules/ions BF3, NO2-, NH2- and H2O, the central atom is sp2 hybridised?
NO2- and NH2-
NH2- and H2O
NO2- and H2O
NO2- and H2O
The angular shape of ozone molecule (O3) consists of
1 sigma and 2 pi bonds
2 sigma and 2 pi bonds
1 sigma and 1 pi bonds
1 sigma and 1 pi bonds
Four diatomic solutions of the following were prepared in water separately. Which one of the solutions will record the highest pH?
Bond dissociation enthalpy of H2, Cl2 and HCl and 434, 242 and 431 kJ mol-1 respectively. Enthalpy of formation of HCl is
93 kJ mol-1
-245 kJ mol-1
-39 kJ mol-1
-39 kJ mol-1
In the hydrocarbon
The state of hybridization of carbon 1, 3, and 5 are in the following sequence
sp2, sp, sp3
sp, sp3, sp2
sp, sp2, sp3
sp, sp2, sp3
The correct order of C-O bond length among CO, CO32-, CO2 is,
CO2< CO32-< CO
CO < CO32-< CO2
CO32- <CO2 <CO
CO32- <CO2 <CO
B.
CO < CO32-< CO2
The bond length is the average distance between the centres of nuclei of two bonded atoms. Centres of nuclei of two bonded atoms. A multiple bonds (double or triple bond) is always shorter than the corresponding single bond.
The C- atom is CO32- is sp2 hybridised as shown
The C- atom is CO2 is sp hybridised with a bond distance of carbon -oxygen is 122 pm.
The C- atom in CO is sp hybridised with C-O bond distance is 110 pm:
So the correct order is
CO < CO32-< CO2