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 Multiple Choice QuestionsMultiple Choice Questions

181.

Assertion : SeCl4 does not have a tetrahedral structure.

Reason : Se in SeCl4 has two lone pairs.

  • If both assertion and reason are true and reason is the correct explanation of assertion.

  • If both assertion and reason are true but reason is not the correct explanation of assertion.

  • If assertion is true but reason is false.

  • If both assertion and reason are false.


182.

Intermolecular hydrogen bonding is strongest in :

  • C2H5OH

  • HF

  • H2O

  • CH3COCH3


183.

Hybridization present in ClF3 is :

  • sp2

  • sp3

  • dsp2

  • sp3d


184.

Number of electrons surrounding Kr in KrF2 is :

  • 10

  • 6

  • 4

  • 8


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185.

H - I - O bond angle in H2O2 :

  • 90o

  • 180o

  • 109.5o

  • 94.8o


186.

Assertion : Molecular nitrogen is less reactive than molecular oxygen.

Reason : The bond length of N2 is shorter than that of oxygen.

  • If both assertion and reason are true and reason is the correct explanation of assertion.

  • If both assertion and reason are true but reason is not the correct explanation of assertion.

  • If assertion is true but reason is false.

  • If both assertion and reason are false.


187.

Electron deficient molecule is :

  • CCl4

  • PCl5

  • BF3

  • SF6


188.

Number of unpaired electrons in O2 molecule is :

  • zero

  • one

  • two

  • four


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189.

Bond order in benzene is :

  • 1

  • 2

  • 1.5

  • none of these


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190.

Among the following, the species having square planar geometry for central atom are
(i) XeF4, (ii) SF4, (iii) [NiCl4]2- ,(iv) [PdCl]2-

  • (i) and (iv)

  • (i) and (ii)

  • (ii) and (iii)

  • (iii) and (iv).


A.

(i) and (iv)

XeF: sp3 dhybridisation, shape is square planar instead of octahedral due to presence of two lone pair of electrons on Xe atom. SF4: SF4 molecule shows sp3d hybridisation but its expected trigonal bipyramidal geometry gets distorted due to presence of a lone pair of electrons and it becomes distorted tetrahedral or see-saw with the bond angles equal to 89° and 177° instead of the expected angles of 90° and 180° respectively.

Experiments have, however, shown that 4-coordinated complexes of Pd(II) are diamagnetic (n = 0). Thus it is dsphybridisation which is involved in the formation of (PdCl4]2- ion i.e. 4-coordinated complexes of Pd(II) have square planar geometry with n = 0 (diamagnetic).

 

 


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