The pH of a 10-10M - NaOH solution is
10
7.01
6.99
4
B.
7.01
When the solution is very dilute, the concentration of OH- produced from water cannot be neglected. Hence,
[OH-] = 10-10 + 10-7 (obtained from water)
= 10-7 (0.001 + 1)
= 1.001 10-7
pOH = -log[OH-]
= -log(1.001 10-7)
= 7 - 0.01 = 6.99
pH = 14 - pOH
= 14 - 6.99
= 7.01
Therefore, the pH of a 10-10 - NaOH solution is 7.01
NaOH(aq), HCl(aq), and NaCl(aq) concentration of each is 10-3 M. Their pH will be respectively
10, 6, 2
11, 3, 7
10, 3, 7
10, 4, 7
On adding A to the reaction at equilibrium, AB (s) A(g) + B(g) the new equilibrium concentration of A becomes double, the equilibrium concentration of B would become:
1/2 of its original value
1/4 of its original value
1/8 of its original value
Twice its original value
A solution contains 10 mL of 0.1 N NaOH and 10mL of 0.05 NH2SO4.pH of this solution is:
zero
less than 7
greater than 7
7
Fear or excitement, generally cause one to breathe rapidly and it results in the decrease of concentration of CO2 in blood. In what way it will change pH of blood?
pH will increase
pH will decrease
No change
pH will be 7
A litre solution containing NH4Cl and NH4OH has hydroxide ion concentration of 10-6 mol L-1. Which of the following hydroxide could be precipitated when the solution is added to 1L solution of 0.1M metal ions?
Ba(OH)2 (Ksp = 5 x 10-3)
Ni(OH)2 (Ksp = 1.6 x 10-16)
Mn(OH)2 (Ksp = 2 x 10-13)
Fe(OH)2 (Ksp = 8 x 10-16)
I and IV
III and IV
II and IV
II , III and IV
For the reaction, 2NO2 2NO + O2, the value of Kp is equal to K. What will the value of Kp for reaction,
NO + O2 NO2