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71.

Two small drops of mercury, each of radius R, coalesce to form a single large drop. The ratio of the total surface energies  before and after  change is

  • 1 : 21/3

  • 21/3 : 1

  • 2 : 1

  • 1 : 2


B.

21/3 : 1

Radius of one drop of mercury is R

∴  The volume of one drop = 43π R3

∴  Total volume of the two drops,

  V =  2 × 43π R3

   V = 83 πR3

Let the radius of the large drop formed be R'

The total volume of the large is also V

    43π R'2 = 83π R3

     R'3 = 2R3

⇒   R' = 21/3 R

Now the surface area of the resultant drop is 

   S1 = 2 × 4πR2

   S1 = 8πR

and the surface area of the resultant drop is 

    S2 = 4πR'

    S2 = 4π 22/3 R2

Let T be the surface tension of the mercury. Therefore the surface energy of the two drops before coalescing is

     U1 = S1 T

     U1 = 8πR2T

and the surface energy after coalescing,

    U2 = S2

     U2 = 22/3 × 4πR2T

∴   U1U2 = 8π R2T223 × 4π R2T

           = 2223

    U1U2 = 21/3


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72.

Scent sprayer is based on

  • Charle's law

  • Archimedes principle

  • Boyle's law

  • Bernoulli's theorem


73.

The property utilized in the manufacture of lead shots is

  • specific weight of liquid lead

  • compressibility of liquid lead

  • specific gravity of liquid lead

  • surface tension of liquid lead


74.

Assertion:  Thin films such a soap bubble or a thin layer of oil on water show beautiful colours when illuminated by white light.

Reason:  It happens due to the interference of light reflected from upper surface of the thin film.

  • If both the assertion and reason are true and reason is a correct explanation of assertion.

  • If both assertion and reason are true but assertion is not a correct explanation of the assertion.

  • If both the assertion is true but the reason is false.

  • If both assertion and reason are false.


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75.

For liquid to rise in a capillary tube, the angle of contact should be

  • acute

  • obtuse

  • right

  • none of these


76.

Which of the following physical wuantity do not have same dimensions?

  • pressure and stress

  • tension and surface tension

  • strain and angle

  • energy and work


77.

The length of a needle floating on water is 2.5 cm. Calculate the added force (due to surface tension) required to pull the needle out of water. (Surface tension of water = 7.2× 10-2 N/m2)

  • 3.6 × 10-3 N

  • 3.4 × 10-10 N

  • 3.0 × 10-5 N

  • 3.8 × 10-11 N


78.

A capillary tube of radius r is immersed in water and water rises in it to a height H. Mass of water in the capillary tube is m. If the capillary of radius 2r is taken and dipped in water, the mass of water that will rise in the capillary tube will be

  • m

  • 2 m

  • m/2

  • 4 m


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79.

The work done in increasing the size of a soap film from 10 cm x 6 cm to 10 cm x 11 cm is 3 x 10-4 J. The surface tension of the film is

  • 1.5 × 10-2 N/m

  • 3 × 10-2 N/m

  • 6.0 × 10-2 N/m

  • 11 × 10-2 N/m


80.

The maximum force in addition to the weight required to pull a wire 5.0 cm long from the surface of the water at temperature 20°C, is 728 dyne. The surface tension of water is

  • 7.28 N/cm

  • 7.28 dyne/cm

  • 72.8 dyne/cm

  • 7.28 × 102 dyne/cm


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