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 Multiple Choice QuestionsMultiple Choice Questions

181.

The well-known compounds, (+)- lactic acid and (-)- lactic acid, have the same molecular formula, C3H6O3. The correct relationship between them is:

  • constitutional isomerism

  • geometrical isomerism

  • identicalness

  • optical isomerism


182.

Which one of the following characteristics belong to an electrophile?

  • It is any species having electron deficiency which reacts at an electron-rich C-centre

  • It is any species having electron enrichment, that reacts at an electron-deficient C-centre

  • It is cationic in nature

  • It is anionic in nature


183.

Among the following structures the one which is not a resonating structure of others is

  • I

  • II

  • III

  • IV


184.

Among the following carbocations:

Ph2C+CH2Me (I), PhCH2CH2CH+Ph (II), Ph2CHCH+Me (III) and Ph2C(Me)CH2 (IV), the order of stability is:

  • IV > II > I > III

  • I > II > III > IV

  • II > I > IV > III

  • I > IV > III > II


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185.

Which one of the following will show optical isomerism?

  • OH-CH2-CO2H

  • CH3-CH(OH)-CO2H

  • (CH3)2-CH-CO2H

  • (CH3)2-C(Cl)-CO2H


B.

CH3-CH(OH)-CO2H

2-hydroxypropanoic acid has a central carbon atom, which is linked to four different groups. This carbon atom is called chiral carbon atom and the molecule is called a chiral molecule. Hence, 2-hydroxy propanoic acid shows optical isomerism.

Enantiomers


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186.

Among the following statements about the molecules X and Y, the one(s) which correct is (are)

  • X and Y are diastereomers

  • X and Y are enantiomers

  • X and Y are both aldohexoses

  • X is a D-sugar and Y is an L-sugar


 Multiple Choice QuestionsShort Answer Type

187.

Explain why aniline is not as basic as ammonia.


 Multiple Choice QuestionsMultiple Choice Questions

188.

The two structures written below represent

             

  • pair of diastereomers

  • pair of enantiomers

  • same molecule

  • both are optically inactive


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189.

Which of the following carbocations will be most stable ?

  • Ph3C+

  • CH3-C+H2

  • (CH3)2C+H

  • CH2=CH-C+H2


190.

A compound is formed by substitution of two chlorine for two hydrogens in propane. The number of possible isomeric compounds is

  • 4

  • 3

  • 2

  • 5


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