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 Multiple Choice QuestionsMultiple Choice Questions

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61.

A solution contains 25% H2O , 25% C2H5OH and 50% CH3COOH by mass .The mole fraction of H2O would be :

  • 0.25

  • 2.5

  • 0.502

  • 5.03


C.

0.502

Mole fraction of H2O = number of moles of H2Ototal number of moles of all components

Let the total mass of solution = 100 g

Mass of H2O = 25 g

Mass of C2H5OH = 25g

Mass of CH3COOH = 50 g

Moles of H2O = 2518 = 1.388

( Molar mass of H2O = 18)

Moles of C2H5OH =2546 = 0.543

( Molar mass of C2H5OH = 46)

Moles of CH3COOH = 5060 = 0.833

( Molar mass of CH3COOH = 60)

Total no. of moles = 1.388 + 0.543 + 0.833  = 2.764

 Mole fraction of H2O = 1.3882.764 = 0.502


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62.

An organic substance containing carbon , hydrogen and oxygen gave the following percentage composition .

C = 40.687 % , H = 5.085% and O = 54.228 % 

What is the empirical formula of the compound ?

  • CH3O

  • C2H2O

  • CH4O

  • C2H3O2


63.

How many grams of CO2 will be produced by the complete combustion of 2 moles of ethanol ?

  • 132 g

  • 44 g

  • 176 g

  • 88 g


64.

Which of the following changes with change in temperature ?

  • Mole fraction

  • Formality

  • % (w/W)

  • Molality


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65.

Equal weight of CO and CH4 are mixed together in an empty container at 300 K. The fraction of total pressure exerted by CH4 is.

  • 1617

  • 711

  • 89

  • 516


66.

The molarity of a 0.2 N Na2CO5 solution will be :

  • 0.05 M

  • 0.2 M

  • 0.4 M

  • 0.1 M


67.

Ksp of CaSO4.5H2O is 9 ×10-6, find the volume for 1 g of CaSO4 (M.wt. = 136).

  • 2.45 litres

  • 5.1 litres

  • 4.52 litres

  • 3.2 litres


68.

Which ofthe following sequence contains atomic number of only representative elements?

  • 55,12,48,53

  • 13,33,54,80

  • 3,33,53,87

  • 22,33,55,66.


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69.

100 cm3 of a given sample of H2O2 gives 1000 cm3 of O2 at S.T.P. The given sample is

  • 10% H2O2

  • 90% H2O2

  • 10 volume H2O2

  • 100 volume H2O2


70.

Molarity of a given orthophosphoric acid solution is 3 M .It's normality is :

  • 9 N

  • 0.3 N

  • 3 N

  • 1 N


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