CBSE
In the circuit shown the cells A and B have negligible resistances. For VA = 12V, R1 = 500Ω and R = 100Ω the galvanometer (G) shows no deflection. The value of VB is
4V
2V
12 V
12 V
A circuit contains an ammeter, a battery of 30 V and a resistance 40.8 Ω all connected in series. If the ammeter has a coil of resistance 480 Ω and a shunt 20 Ω then reading in the ammeter will be
0.5 A
0.25 A
2 A
2 A
A potentiometer circuit has been set up for finding the internal resistance of a given cell. The main battery, used across the potentiometer wire, has an emf of 2.0 V and a negligible internal resistance. The potentiometer wire itself is 4 m long. When the resistance R, connected across the given cell, has values of i) infinity ii) 9.5 ohm the balancing lengths on the potentiometer wire are found to be 3 m and 2.85 m, respectively. The value of internal resistance of the cell is,
0.25 ohm
0.95 ohm
0.5 ohm
0.5 ohm
A wire of resistance 4Ω is stretched to twice its original length. The resistance of stretched wire would be
2Ω
4Ω
8Ω
8Ω
The resistance of the four arms P, Q, R and S a Wheatstone's bridge are 10Ω, 30Ω and 90Ω respectively. The emf and internal resistance of the cell are 7V and 5Ω respectively. If the galvanometer resistance is 50Ω, the current drawn from the cell will be
1.0 A
0.2 A
0.1 A
0.1 A
A uniform electric field and a uniform magnetic field are acting along the same direction in a certain region. If an electron is projected in the region such that its velocity is pointed along direction of fields, then the electron
speed will decrease
speed will increase
will turn towards the left of the direction of motion
will turn towards the left of the direction of motion
If power dissipated in the 9Ω resistor in the circuit shown is 36 W, the potential difference across the 2Ω resistor is
8 V
10 V
2 V
2 V
In an ammeter 0.2 % of the main current passes through the galvanometer. If resistance of galvanometer is G, the resistance of ammeter will be,
1/499 G
499/500 G
1/500 G
1/500 G
A current 2 A flows through a 2 Ω resistor when connected across a battery. The same battery supplies a current of 0.5 A when connected across a 9 Ω resistor. The internal resistance of the battery is
1/3 Ω
1/4 Ω
1 Ω
1 Ω
The internal resistance of a 2.1 V cell which gives a current of 0.2 A through of 0.2A through a resistance of 10Ω is
0.2Ω
0.5Ω
0.8Ω
0.8Ω