CBSE
Multiple Choice QuestionsThe period of oscillation of a simple pendulum of constant length at the surface of the earth is T. Its time period inside a mine will be :
can not be compared
equal to T
less than T
more than T
The radius of orbit of satellite of earth is R. Its kinetic energy is proportional to :
R
A body falls from a height h = 200 m. The ratio of distance travelled in each 2 sec, during t = 0 to t = 6 second of the journey is
1 : 4 : 9
1 : 2 : 4
1 : 3 : 5
1 : 2 : 3
The radius of orbit of a planet is two times that of the earth. The time period of the planet is :
4.2 T
2.8 T
5.6 T
8.4 T
Two satellites A and B go around a planet P in circular orbits having radius 4 R and R respectively. If the speed of satellite A is 3v, then the speed of satellite B will be
6v
9v
3v
none of these
According to Kepler's law, the time period of a satellite varies with its radius are as:
T2 ∝ R3
T3 ∝ R2
The distance between the sun and the earth be r then the angular momentum of the earth around the sun is proportional to :
r
none of these
Acceleration due to gravity:
decreases from the equator to poles
decreases from poles to the equator
is maximum at the centre of the earth
is maximum at the equator
A particle falls towards earth from infinity. Its velocity on reaching the earth would be:
infinity
zero
The length of the second's pendulum is 1 m on earth. If the mass and diameter of a planet are doubled than that of earth. Then its length becomes
1 m
2 m
0.5 m
4 m
