CBSE
A particle is executing two different simple harmonic motions, mutually perpendicular, of different amplitudes and having a phase difference of π/2. The path of the particle will be :
circular
straight line
parabolic
elliptical
Two pendulums of lengths 100 cm and 121 cm start vibrating. At some instant the two are at the mean position in the same phase. After how many vibrations of the longer pendulum will the two be in the same phase at the mean position again?
10
11
20
21
The false statement is
Every SHM is periodic in nature
Every periodic motion is SHM
In every SHM, total energy is proportional to the square of amplitude
In SHM, acceleration of oscillating body is proportional to the displacement from the equilibrium position
A particle is executing the motion x = a cos (ωt - θ). The maximum velocity of the particle is :
aω cosθ
aω
aω sinθ
none of these
Equations of motion in the same direction are given by :
y1 = 2a sin(ωt - kx)
y2 = 2a sin(ωt - kx - θ)
The amplitude of the medium particle will be:
2a cosθ
a cosθ
4 a cos
A particle executing SHM has amplitude 0.01 m and frequency 60 Hz. The maximum acceleration of the particle is :
A particle executing simple harmonic motion has a time period of 4 sec. After how much interval of time from t = 0 will its displacement be half of its amplitude :
1/3 sec
1/2 sec
2/3 sec
1/6 sec
When a wave travels in a medium, the particle's displacement is given by the equation
y = 0.03 sin(2t - 0.01 x)
where x and y are in metre and t in second. The wavelength of the wave is :
200 m
100 m
20 m
10 m
A child swinging on a swing in sitting position, stands up, then the time period of swing will
increase
decrease
remain same
increase if the child is long and decrease if the child is short
To make the frequency double of a spring oscillator, we have to :
reduce the mass to one fourth
quadruple the mass
double the mass
half the mass