CBSE
Two identical springs are connected to mass m as shown (k = spring constant). If the period of the configuration in (a) is 2s, the period of the configuration in (b) is
1 s
The time period of the second's hand of a watch is
1 h
1 s
12 h
1 min
A particle is executing linear simple harmonic motion of amplitude A. At what displacement is the energy of the particle half potential and half kinetic ?
A spring of force constant k is cut into two equal halves. The force constant of each half is
k
2k
Two massless springs of force constants k1 and k2 are joined end to end. The resultant force constant k of the system is
A particle executes linear simple harmonic motion with an amplitude of 2 cm. When the particle is at 1 cm from the mean position the magnitude of its velocity is equal to that of its acceleration . Then its time period in second is
A particle starts SHM from the mean position. Its amplitude is a and total energy E. At one instant its kinetic energy is 3 · Its displacement at that instant is
A spring of force constant k is cut into three equal parts. The force constant of each part would be
3k
k
2k
A particle of mass m is attached to three identical massless springs of spring constant k as shown in the figure. The time period of vertical oscillation of the particle is
Two springs are joined and attached to a mass of 16 kg. The system is then suspended vertically from a rigid support. The spring constant of the two springs are k1 and k2 respectively. The period of vertical oscillations of the system will be