In the given figure, a triangle ABC is drawn to circumscribe of

Subject

Mathematics

Class

CBSE Class 10

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 Multiple Choice QuestionsShort Answer Type

1.

If the quadratic equation haspx squared minus 2 square root of 5px plus 15 equals 0 two roots, then find the value of p.

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2.

In Given figure, a tower AB is 20 m high and BC, its shadow on the ground, is m20 square root of 3 long. Find the sun's altitude.

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3.

The different dice are tossed together. Find the probability that the product of the two number on the top of the dice is 6.

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4.

In the given figure, PQ is a chord of a circle with centre O and PT is tangent. If ∠QPT = 60o, find ∠ PRQ.

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5.

In the given figure, two tangents RQ and RP are drawn from an external point R to the circle with centre O. If ∠PRQ = 120o, then prove that OR = PR + RQ.

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6.

In the given figure, a triangle ABC is drawn to circumscribe of radius 3 cm, such that the segments RD and DC are respectively of length 6 cm and 9 cm. If the area of ΔABC is 54 cm2, then find lengths of sides AB and AC.


Suppose the given circle touch the sides AB and AC of the triangle at point F and E, respectively. Let the length of the line segment AF is x cm.


We know that the length of tangents drawn from an external point to a circle are equal.

In ΔABC,

CE = CD = 9 cm (Tangents of the circle from point C)

BF = BD = 6 cm (Tangents on the circle from point B)

AE = AF + FB = x + 6

BC = BD + DC = 6 + 9 = 15

CA = CE + EA  = 9 + x

Area space of space increment OBC space equals space 1 half space straight x space BC space straight x space OD space
space equals space 1 half space straight x space 15 space straight x space 3 space equals space 45 over 2

Area space of space increment OCA space equals space 1 half space straight x space AC space straight x space OE space
equals 1 half space straight x space left parenthesis straight x plus 9 right parenthesis space straight x space 3 space equals space 3 over 2 left parenthesis straight x space plus space 9 right parenthesis

Area space of space increment OAB space equals space 1 half space straight x space AB space straight x space OF
equals 1 half space straight x space left parenthesis space straight x space plus space 6 right parenthesis space straight x space 3 space space equals space 3 over 2 space left parenthesis space straight x space plus space 6 right parenthesis

Area space of space increment ABC space equals space Area space of space increment OBC space plus increment OCA space plus Area space of space increment OAB
space 54 space equals space 45 over 2 space plus 3 over 2 space left parenthesis straight x space plus space 9 right parenthesis space plus 3 over 2 space left parenthesis space straight x space plus space 6 right parenthesis

rightwards double arrow space 54 space equals space 45 space plus space 3 straight x space

rightwards double arrow space 3 space straight x space equals space 54 space minus space 45

rightwards double arrow space straight x space equals space 3

Therefore comma

AB space equals space straight x plus space 6 space equals space 3 space plus space 6 space equals space 9 space cm

and space AC space equals space 9 space plus space straight x space equals space 9 space plus space 3 space equals space 12 space cm

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7.

Solve the following quadratic equation for x,

4x2 + 4bx - (a2 - b2) = 0

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8.

In an AP, if S5 + S7 = 167 and S10 = 235, then find the AP,  Where Sn denotes the sum of its first n terms.

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9.

The points A (4, 7), B (p, 3) and C (7, 3) are the vertices a right triangle, right-angled at B find the value of p.

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10.

Find the relation between x and y if the points A (x, y), B (-5, 7) and C (-4, 5) are collinear.

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