(a) Write the structures of the main product when acetone ( CH3-CO-CH3) reacts with the following reagent:
(i) Zn-Hg/conc. HCl
(ii) H2N-NHCONH2/H+
(iii) CH3MgBr and then H3O+
(a) Arrange the following in the increasing order of their boiling point:
C2H5OH, CH3-CHO, CH3-COOH
(b) Give a simple chemical test to distinguish between the following pair of compounds:
CH3CH2CHO and CH3CH2COCH3
(i) Acetone undergoes clemmensen reduction in presence of zinc amalgam and conc.HCl to give propane.
(ii) Acetone reacts with semicarbazide to form semicarbazone.
(iii) Acetone reduces to form tertiary alcohol in the presence of Grignard reagent.
(b) Due to extensive hydrogen bonding, carboxylic acid has the highest boiling points an among the given compound. Alcohols, with a smaller number of the hydrogen bond, have a lesser boiling point. Aldehydes have least boiling point due to the absence of hydrogen bonding.
Hence the order of boiling point is:
CH3-CHO < C2H5OH < CH3COOH
(c) 2- Butanone has a methyl group attached to carbonyl carbon unlike propanal .hence , it can give iodoform test.
CH3CH2COCH3 CH3CH2COOH + CHI3
(Yellow ppt.)
CH3CH2CHO No reaction
Propanal