A line passing through the point A with position vector  is pa

Subject

Mathematics

Class

CBSE Class 12

Pre Boards

Practice to excel and get familiar with the paper pattern and the type of questions. Check you answers with answer keys provided.

Sample Papers

Download the PDF Sample Papers Free for off line practice and view the Solutions online.
Advertisement

 Multiple Choice QuestionsShort Answer Type

Advertisement

21.

A line passing through the point A with position vector straight a with rightwards arrow on top space equals space 4 straight i with hat on top plus 2 straight j with hat on top plus 2 straight k with hat on top is parallel to the vector straight b with rightwards arrow on top space equals space 2 straight i with hat on top plus 3 straight j with hat on top plus 6 straight k with hat on top. Find the length of the perpendicular drawn on this line from a point p with vector stack straight r subscript 1 with rightwards arrow on top space equals straight i with hat on top plus 2 straight j with hat on top plus 3 straight k with hat on top.


Let the equation of the line be straight r with rightwards arrow on top space equals space straight a with rightwards arrow on top space plus space straight lambda straight b with rightwards arrow on top
 Here comma space straight a with rightwards arrow on top space equals space 4 straight i with hat on top plus 2 straight j with hat on top plus 2 straight k with hat on top
straight b with rightwards arrow on top equals space 2 straight i with hat on top plus 3 straight j with hat on top plus 6 straight k with hat on top
therefore space Equation space of space the space line space is space straight r with rightwards arrow on top space equals space 4 straight i with hat on top plus 2 straight j with hat on top plus 2 straight k with hat on top plus bold lambda left parenthesis 2 straight i with hat on top plus 3 straight j with hat on top plus 6 straight k with hat on top right parenthesis
Let space straight L space be space the space foot space of space the space perpendicular space and space straight P space be space the space required space point space from
which space we space have space to space find space the space length space of space the space perpendicular
straight P open parentheses straight alpha with rightwards arrow on top close parentheses space equals straight i with hat on top plus 2 straight j with hat on top plus 3 straight k with hat on top
PL with rightwards arrow on top space equals space Position space of space vector space of space straight L space minus space Position space vector space of space straight P
space space space space space space equals 4 straight i with hat on top plus 2 straight j with hat on top plus 2 straight k with hat on top plus straight lambda open parentheses 2 straight i with hat on top plus 3 straight j with hat on top plus 6 straight k with hat on top close parentheses minus open parentheses straight i with hat on top plus 2 straight j with hat on top plus 3 straight k with hat on top close parentheses
space space space space space space equals 3 straight i with hat on top minus straight k with hat on top plus straight lambda open parentheses 2 straight i with hat on top plus 3 straight j with hat on top plus 6 straight k with hat on top close parentheses space.... left parenthesis straight i right parenthesis
Now 
PL with rightwards arrow on top. space straight b with rightwards arrow on top space equals space 0 left square bracket Since space PL with rightwards arrow on top space is space perpendicular space to space straight b with rightwards arrow on top right square bracket
space space open square brackets 3 straight i with hat on top minus straight k with hat on top plus straight lambda open parentheses 2 straight i with hat on top plus 3 straight j with hat on top plus 6 straight k with hat on top close parentheses close square brackets. space open parentheses 2 straight i with hat on top plus 3 straight j with hat on top plus 6 straight k with hat on top close parentheses equals 0
space rightwards double arrow open square brackets straight i with hat on top left parenthesis 3 plus 2 straight lambda right parenthesis plus straight j with hat on top left parenthesis 3 straight lambda right parenthesis plus space straight k with hat on top left parenthesis negative 1 plus 6 straight lambda right parenthesis close square brackets. space open parentheses 2 straight i with hat on top plus 3 straight j with hat on top plus 6 straight k with hat on top close parentheses space equals space 0
space rightwards double arrow left parenthesis 3 plus 2 straight lambda right parenthesis 2 plus left parenthesis 3 straight lambda right parenthesis 3 plus left parenthesis negative 1 plus 6 straight lambda right parenthesis 6 space equals space 0
space space rightwards double arrow 6 plus 4 straight lambda plus 9 straight lambda minus 6 plus 36 straight lambda space equals space 0
space space space rightwards double arrow 49 straight lambda space equals space 0
space space space space space therefore space space straight lambda space equals space 0
space space PL with rightwards arrow on top equals 3 straight i with hat on top minus straight k with hat on top space left square bracket from space left parenthesis ii right parenthesis right square bracket
space space open vertical bar PL with rightwards arrow on top close vertical bar space equals open vertical bar square root of 3 squared plus left parenthesis negative 1 right parenthesis squared end root close vertical bar
space space therefore space space open vertical bar PL with rightwards arrow on top close vertical bar space equals space square root of 10


space space space space space
Length of the perpendicular drawn on the line from P = square root of 10

686 Views

Advertisement
22. If space straight y space equals space straight e to the power of ax. cosbx comma space then space prove space that
space space space fraction numerator straight d squared straight y over denominator dx squared end fraction minus 2 straight a dy over dx plus left parenthesis straight a squared plus straight b squared right parenthesis straight y space equals space 0
516 Views

23. If space straight x to the power of straight x plus straight x to the power of straight y plus straight y to the power of straight x space equals space straight a to the power of straight b comma space space then space find space dy over dx.
513 Views

24.

If straight x equals straight a space sin space 2 straight t left parenthesis 1 plus cos space 2 straight t right parenthesis space and space straight y space equals straight b space cos space 2 straight t left parenthesis 1 minus cos space 2 straight t right parenthesis comma space then space find dy over dx space at space straight t space equals straight pi over 4.

783 Views

Advertisement
25.

Evaluate: integral fraction numerator left parenthesis straight x plus 3 right parenthesis straight e to the power of straight x over denominator left parenthesis straight x plus 5 right parenthesis cubed end fraction dx

519 Views

26.

Three schools X, Y, and Z organized a fete (mela) for collecting funds for flood victims in which they sold hand-held fans, mats and toys made from recycled material, the sale price of each being Rs. 25, Rs. 100 andRs. 50 respectively. The following table shows the number of articles of each type sold:
School/Article                     School X                   School Y                School Z
Hand-held fans                         30                         40                         35
      Mats                                  12                         15                         20
       Toys                                 70                         55                         75
Using matrices, find the funds collected by each school by selling the above articles and the total funds collected. Also write any one value generated by the above situation. 

633 Views

 Multiple Choice QuestionsLong Answer Type

27.

Sketch the region bounded by the curves straight y equals square root of 5 minus straight x squared end root space and space straight y space equals open vertical bar straight x minus 1 close vertical bar and find its area using integration. 

600 Views

28.

Find the particulars solution of the differential equation straight x squared dy space equals space left parenthesis 2 xy plus straight y squared right parenthesis dx comma space given that y =1 when x = 1.

438 Views

Advertisement
29.

Find the particulars solution of the differential equation left parenthesis 1 plus straight x squared right parenthesis dy over dx equals open parentheses straight e to the power of straight m space tan to the power of negative 1 straight x end exponent end exponent minus straight y close parentheses comma space given space that space straight y space equals space 1 space when space straight x space equals space 0.

315 Views

30.

Show that lines:
straight r with rightwards arrow on top space equals space straight i with hat on top space plus straight j with hat on top space plus straight k with hat on top space plus space straight lambda open parentheses straight i with hat on top minus straight j with hat on top space plus space straight k with hat on top close parentheses
straight r with rightwards arrow on top space equals space 4 straight j with hat on top space plus space 2 straight k with hat on top space plus space straight mu open parentheses 2 straight j with hat on top minus straight j with hat on top plus 3 straight k with hat on top close parentheses space are space coplanar.
Also, find the equation of the plane containing these lines. 

477 Views

Advertisement