A light bulb is rated 100 W for 220 V ac supply of 50 Hz. Calcul

Subject

Physics

Class

CBSE Class 12

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Sample Papers

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 Multiple Choice QuestionsShort Answer Type

1.

Two wires of equal length, one of copper and the other of manganin have the same resistance. Which wire is thicker?

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2.

What are the directions of electric and magnetic field vectors relative to each other and relative to the direction of propagation of electromagnetic waves?     

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3.

A bar magnet is moved in the direction indicated by the arrow between two coils PQ and CD.

Predict the directions of induced current in each coil. 


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4.

Mention the two characteristic properties of the material suitable for making core of a transformer. 

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5.

A charge ‘q’ is placed at the centre of a cube of side l. What is the electric flux passing through each face of the cube? 

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6.

A test charge ‘q’ is moved without acceleration from A to C along the path from A to B and then from B to C in electric field E as shown in the figure. (i) Calculate the potential difference between A and C. (ii) At which point (of the two) is the electric potential more and why? 


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7.

An electric dipole is held in a uniform electric field.

(i) Show that the net force acting on it is zero.

(ii) The dipole is aligned parallel to the field. Find the work done in rotating it through the angle of 180°.

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8.

State the underlying principle of a transformer. How is the large scale transmission of electric energy over long distances done with the use of transformers?  

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9.

A capacitor of capacitance of ‘C’ is being charged by connecting it across a dc source along with an ammeter. Will the ammeter show a momentary deflection during the process of charging? If so, how would you explain this momentary deflection and the resulting continuity of current in the circuit? Write the expression for the current inside the capacitor.

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10.

A light bulb is rated 100 W for 220 V ac supply of 50 Hz. Calculate

(a) the resistance of the bulb;

(b) the rms current through the bulb

 

OR

 

An alternating voltage given by V = 140 sin 314 t is connected across a pure resistor of 50 W. Find

(i) the frequency of the source.

(ii) the rms current through the resistor. 


straight a right parenthesis thin space straight R space equals space straight V squared subscript rms over straight P space equals space fraction numerator 220 space straight x space 220 over denominator 100 end fraction space equals space 48 space straight capital omega

straight b right parenthesis thin space straight I subscript rms space equals space straight P over straight V subscript rms straight x 100 over 220 space equals space 0.45 space straight A  


                                                             OR


straight i space right parenthesis thin space straight V space equals space 140 space sin space 314 space straight t

because space straight V space equals space straight V subscript straight o space sin space straight omega space straight t

Hence comma space straight omega space equals space 314 space space space

rightwards double arrow space 2 πν space equals space 314 space

rightwards double arrow space straight nu space equals space 50 space Hz

ii right parenthesis
straight V subscript rms space equals space fraction numerator straight V subscript straight o over denominator square root of 2 end fraction space equals space fraction numerator 140 over denominator square root of 2 end fraction space equals space 98.9 space straight V

straight I space equals space straight V subscript rms over straight R equals fraction numerator 98.9 over denominator 50 end fraction space equals space 1.97 space straight A


 
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