Depict the orientation of the dipole in (i) stable, (ii) unstabl

Subject

Physics

Class

CBSE Class 12

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 Multiple Choice QuestionsShort Answer Type

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2.

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3.

At a place, the horizontal component of earth's magnetic field is B and angle of dip are 60o. What is the value of a horizontal component of the earth's magnetic field at the equator?


4.

How is the speed of em-waves in vacuum determined by the electric and magnetic field?

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5.

How does Ampere-Maxwell law explain the flow of current through a capacitor when it is being charged by a battery? Write the expression for the displacement current in terms of the rate of change of electric flux. 

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6.

(i) Find the value of the phase difference between the current and the voltage in the series LCR circuit shown below. Which one leads in phase: current or voltage?

(ii) Without making any other change, find the value of the additional capacitor C, to be connected in parallel with the capacitor C, in order to make the power factor of the circuit unity.

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7.

A resistance of R draws current from a potentiometer. The potentiometer wire, AB, has a total resistance of Ro. A voltage V is supplied to the potentiometer. Derive an expression for the voltage across R when the sliding contact is in the middle of potentiometer wire.

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8.

(i) Find equivalent capacitance between A and B in the combination given below. Each capacitor is of 2μF capacitance.

(ii) If a dc source of 7 V is connected across AB, how much charge is drawn from the source and what is the energy stored in the network?

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9.

Drive the expression for electric field at a point on the equatorial line of an electric dipole.

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10.

Depict the orientation of the dipole in (i) stable, (ii) unstable equilibrium in a uniform electric field.


Depicting the orientation of the dipole in (i) stable equilibrium in a uniform electric field.

Net force is zero in this case as qE-qE = 0
Net torque =pEsinθ as θ = 0


(ii) Unstable equilibrium in a uniform electric field.

Net force is negative in this case as-qE-qE = -2qE
Net torque = pEsinθ asθ = 180

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