Given,

Height (in cm)	No. of Students	Cumulative frequency(c.f.)
140 – 145	12	12
145 – 150	20	32
150 – 155	30	62
155 – 160	38	100
160 – 165	24	124
165 – 170	16	140
170 – 175	12	152
175 – 180	8	160
	N = 160

Taking scale as 2 cm=5 cm on x-axis and 2 cm = 20 students on the y- axis, the Ogive is drawn as below:

(i) Median Height = $(\frac{\mathrm{N}}{2}{)}^{\mathrm{th} }$ value = $(\frac{160}{2}{)}^{\mathrm{th}}$ value = 80^th value = 157 cm

(ii) Lower quartile, Q₁ = $(\frac{\mathrm{N}}{4}{)}^{\mathrm{th}} \mathrm{value}$ = $(\frac{160}{4}{)}^{\mathrm{th}}$ value = 40^th value = 152 cm.

Upper quartile, Q₃ = $(\frac{3\mathrm{N}}{4}{)}^{\mathrm{th} }\mathrm{value}$ = $(\frac{3 \times 160}{4}{)}^{\mathrm{th}}$ value = 120^th value = 164 cm

Thus, Inter Quartile range = 164 - 152 = 12 cm

(iii) The number of students whose height is more than 172 cm = 160 - 142 = 18 students.