In the given figure, ∆BAD = 65°, ∆ABD = 70°,

Subject

Mathematics

Class

ICSE Class 10

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 Multiple Choice QuestionsShort Answer Type

1.

Given A = 2- 620, B = - 3240, C = 4002

Find the matrix X such that A + 2X = 2B + C.


2.

At what rate % p.a. will a sum of Rs. 4000 yield Rs. 1324 as compound interest in 3 years?


3.

The median of the following observation 11, 12, 14, (x - 2), (x + 4), (x + 9), 32, 38, 47 arranged in ascending order is 24.

Find the value of x and hence find the mean.


4.

What number must be added to each of the numbers 6, 15, 20 and 43 to make them proportional?


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5.

If (x – 2) is a factor of the expression 2x3 + ax2 + bx – 14 and when the expression is divided by (x – 3), it leaves a remainder 52, find the values of a and b.


6.

Draw a histogram from the following frequency distribution and find the mode from the graph:
Class 0 - 5 5 - 10 10 - 15 15 - 20 20 -25 25 - 30
Frequency 2 5 18 14 8 5

 


7.

Without using tables evaluate:
3cos80°.csc10° + 2sin59°.sec31°


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8.

In the given figure, BAD = 65°, ABD = 70°, BDC = 45°

(i) Prove that AC is a diameter of the circle.

(ii) Find ACB


(i) In ABD, DAB + ABD + ADB = 180°

 65° + 70° + ADB = 180°

 ADB = 180° - 70° - 65° = 45°

Now, ADC = ADB + BDC = 45° + 45° = 90°

ADC is the angle of semi-circle

So, AC is a diameter of the circle.

(ii) ACB = ADB (angle subtended by the same segment)

 ACB = 45°


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9.

AB is a diameter of a circle with centre C = (– 2, 5). If A = (3, – 7). Find

(i) the length of radius AC

(ii) the coordinates of B.


10.

Solve the following equation and calculate the answer correct to two decimal places:

x2 – 5x – 10 = 0.


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