A shopkeeper purchases a certain number of books for Rs. 960. If the cost per book was Rs. 8 less, the number of books that could be purchased for Rs. 960 would be 4
more. Write an equation, taking the original cost of each book to be Rs. x, and solve it to find the original cost of the books.
Given below are the entries in a Saving Bank A/c pass book.
Date | Particulars | Withdrawls | Deposit | Balance |
Feb 8 | B/F | - | - | Rs.8500 |
Feb 18 | To self | Rs. 4000 | - | |
April 12 | By cash | - | Rs. 2230 | |
June 15 | To self | Rs. 5000 | - | |
July 8 | By cash | - | Rs. 6000 |
Calculate the interest for six months from February to July at 6% p.a.
On completing given passbook, we get
Date | Particulars | Withdrawls | Deposit | Balance |
Feb 8 | B/F | - | - | Rs.8500 |
Feb 18 | To self | Rs. 4000 | - | |
April 12 | By cash | - | Rs. 2230 | |
June 15 | To self | Rs. 5000 | - | |
July 8 | By cash | - | Rs. 6000 |
Principal for the month of Feb = Rs. 4500
Principal for the month of March = Rs. 4500
Principal for the month of April = Rs. 4500
Principal for the month of May = Rs. 6730
Principal for the month of June = Rs. 1730
Principal for the month of July = Rs. 7730
Thus, Total Principal for 1 month = Rs. (4500 + 4500 + 4500 + 6730 + 1730 + 7730)
= Rs. 29690
Therefore, P = Rs. 29690, T = Years, R = 6%
We know, Interest =
=
= 148.45rupees = Rs. 148.45