δv = (μ v - 1) A,
δR = (μR- 1) A
δy = (μy - 1) A,
μv = 1.632,
μR = 1.613,
μy = 1.620
This implies,
The threshold wavelength of tungsten is 2400 Å.
When tungsten is illuminated with light of wavelength 1600 Å, find :
(i) Work function
(ii) Maximum kinetic energy of the emitted electron
(iii) Stopping potential.