Subject

Physics

Class

ICSE Class 12

Pre Boards

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Sample Papers

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 Multiple Choice QuestionsShort Answer Type

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21. Obtain an expression for the electric potential at a point which is at a distance r from the point charge Q.


Consider an electric field due to point charge Q placed at point O. Suppose VA is the electric potential at point A, which is at a distance of ra from charge Q.

It W∞ A is the work done in moving a small test charge Q0 from ∞ to A then potential is, 

straight V subscript straight A space equals space straight W over straight Q subscript straight o

                         ... (1)
Consider that at any time, the test charge is at point P. The electric field due to the charge Q exerts force,

space stack straight F space with rightwards harpoon with barb upwards on top equals space minus straight Q subscript straight o space end subscript straight E on the test charge placed at that point P. 
If the test charge Q0 is moved a small distance PB = dl, then small work done is given by, 

dW = F. dl

       = - (QoE). dl

       
= -Qo E dl cos 180o

       =  QoEdl

 dW = 
- QoEdr

Here we have taken dl as - dr, because the distance r decreases in the direction of dl

Since, we know that 

straight E with rightwards harpoon with barb upwards on top space equals space open parentheses fraction numerator 1 over denominator 4 pi epsilon subscript o end fraction. space Q over r squared close parentheses. d r

space space space space equals space space minus fraction numerator 1 over denominator 4 pi epsilon subscript o end fraction. fraction numerator Q Q subscript o over denominator r squared end fraction. d r

H e n c e space w o r k space d o n e comma space

W subscript A space equals integral subscript A superscript B d W space equals space integral subscript r superscript r subscript A end superscript minus space fraction numerator 1 over denominator 4 pi epsilon subscript o end fraction. space fraction numerator Q Q subscript o over denominator r squared end fraction space d r

space space space space space space space equals space minus space fraction numerator 1 over denominator 4 pi epsilon subscript o end fraction. space integral subscript infinity superscript straight r subscript straight A end superscript space straight r to the power of negative 2 end exponent space dr

space space space space space space equals space minus fraction numerator 1 over denominator 4 pi epsilon subscript o end fraction. space QQ subscript straight o open vertical bar space fraction numerator straight r to the power of negative 1 end exponent over denominator negative 1 end fraction close vertical bar
space space space space space space equals space space fraction numerator 1 over denominator 4 πε subscript straight o end fraction space minus QQ subscript straight o space open vertical bar 1 over straight r close vertical bar subscript infinity superscript straight r subscript straight A end superscript

space space space space space space equals space fraction numerator 1 over denominator 4 πε subscript straight o end fraction space minus QQ subscript straight o space open parentheses 1 over straight r subscript straight A minus 1 over straight r subscript straight B close parentheses

space space space space space equals space fraction numerator 1 over denominator 4 πε subscript straight o end fraction. space QQ subscript straight o space open parentheses 1 over straight r subscript straight A minus 0 close parentheses

or space straight W subscript infinity straight A end subscript space equals space fraction numerator 1 over denominator 4 πε subscript straight o end fraction. QQ subscript straight o over straight r subscript straight A space space space space space space space space space space space space space space space space space space space space space space... space left parenthesis 2 right parenthesis 

Using equation (2) in eqn. (1), we get

straight V subscript straight A space equals space fraction numerator 1 over denominator 4 πε subscript straight o end fraction space straight Q over straight r subscript straight A

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22. Find the equivalent capacitance of the following circuit between the junctions A and B; given C1 = C2 = C3 = C4= 10μF and C5 = 5,μF.
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23. A galvanometer with a coil of resistance 100 Cl and a scale having 100 divisions has a current sensitivity of 25 μ A / division.'How will you convert it into an ammeter of range 0 to 5A ? 

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24. The emf ‘E’ of a thermocouple varies with the temperature θ (in degree C) of the hot junction (cold junction at 0°C) as E = 15 q 0.05 q2.

Determine the neutral temperature.  
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25. Using either deflection magnetometer or vibration magnetometer, explain how will you compare magnetic moments of two given bar magnets.
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26. Two very long straight parallel conductors carrying currents I1 and I2 in vacuum are separated by a distance ‘a’. Write an expression for the force experienced per unit length by one wire due to the current flowing through the other wire and hence define the fundamental unit of current, i.e., an ampere. 
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27. When the primary of a transformer is connected to a 120 V AC mains, the current in the primary is 18.5 mA. Find the voltage across the secondary when it delivers 1.5 mA current through it, assuming the transformer to be an ideal one. State any one type of energy loss in a transformer. 
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28. Draw a simple ray diagram showing the formation of a primary rainbow. 
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29. Using Huygen’s Principle, prove the laws of refraction of light. 
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30. The figure below shows the positions of the first bright fringes B1, and B2 on either side of the central bright fringe O in Young’s double slit experiment. Find the wavelength of monochromatic light used.    


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