In the given circuit
Cl = C2 = C3 = C4 = 10 μf
Therefore,
Thus given circuit is a balanced Wheat-Stone Bridge. So the P.d. across the ends of C5 is zero. Capacitance C5 is ineffective.
So equivalent circuit can be made as -Capacitances C1and C2 are in series.
So equivalent capacitance CS is,