Current are distributed as shown in the figure below.
Resistances P, Q, R and S are shown.
Division of current are marked.
Applying KVL to the mesh ABD,
i1P + igG - (i - i1)R = 0 ---(i)
Applying KVL to the mash BCD,
(ii - ig)Q - (i - ii + ig)s - igG =0 ---(ii)
under balanced condition ig = 0
ii P = (i - ii)R ---(iii)
ii Q = (i - ii)S ---(iv)
Dividing eq. (iii) by eq. (iv)
Adjecent figure shows a point P near a long conductor XY carrying a current I. MN is a short current carrying conductor, kept at the point P, parallel to the conductor XY.
(i) What is the direction of magnetic flux density ‘B’ at the point P due to the current flowing through XY?
(ii) What is the direction of the force experienced by the conductor MN due to the current flowing through XY?