Subject

Physics

Class

ICSE Class 12

Pre Boards

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Sample Papers

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 Multiple Choice QuestionsLong Answer Type

21.

a) Two point charges Q1 = 400 μC and Q2 = 100 straight mu space straight C are kept fixed, 60 cm apart in vacuum.Find intensity of the electric field at midpoint of the line joining Q1 and Q2.
b) i) State Gauss' law.

ii) In an electric dipole, at which point is the electrical potential zero?


22.

a) Obtain an expression for equivalent capacitance when three capacitors C1, C2 and C3 are connected in series.

b) A metallic wire has a resistance of 3.0 ohm and 0o Cand 4.8 ohm at 150o C. Find the temperature coefficient of resistance of its material?


23. a) In the circuit shown in figure E1 and E2 are two cells having emfs 2 V and 3 V respectively, and negligible internal resistances. Applying Kirchoff's laws of electrical networks, find the values of currents I1 and I2.
 
b) State how a moving coil galvanometer can be converted into an ammeter.

24.

a) Draw a labelled circuit diagram of a potentiometer to measure internal resistance of a cell. Write the working formula.

b) i) Define Curie temperature.
ii) If magnetic susceptibility of a certain magnetic material is 0.0001, find its relative permeability.


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 Multiple Choice QuestionsShort Answer Type

25.

i) Two infinitely long current carrying conductors X and Y are kept parallel to each other, 24 cm apart in vacuum. They carry currents of 5 A and 7 A respectively, in the same direction, as shown in the figure below. Find the position os a neutral point, i.e., a point where resultant magnetic flux density is zero.



ii) If current through the conductor Y is reversed in direction, will neutral point lie between x and Y, to the left of X or to the left of Y?


26.

i) Define Ampere in terms of force between two current carrying conductors.

ii) What is an ideal transformer.


 Multiple Choice QuestionsLong Answer Type

27.

a) A coil having self-inductance of 0.7 H and resistance of 165 ohm is connected to an ac source of 275 V, 50 Hz. If straight pi space equals space 22 over 7.
Calculate:

i) reactance of the coil
ii) impedance of the coil
iii) current flowing through the coil

b) Draw a labelled graph showing variation of impedance of a series LCR circuit with frequency of the a.c. supply.


28.

a) Derive Snell's law of refraction using Huygen's wave theory.

b) Monochromatic light of wavelength 650 nm falls normally on a slit of width 1.3 x 10-4 and the resulting Fraunhofer diffraction is obtained on a screen. Find the angular width of the central maxima.


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29.

a) In Young's Double Slit experiment, show that:

straight beta space equals space λD over straight d, where the terms have their usual meaning.
b) A ray of ordinary light is travelling in air. It is incident on air-glass pair at a polarising angle of 56o. Find the angle of refraction in glass.


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30. a) Find the angle of incidence at which a ray of monochromatic light should be incident on the first surface AB of a regular glass prism ABC so that the emergent ray grazes the adjacent surface AC. (Refractive index of glass = 1.56)

b) State how focal length of glass lens (refractive index 1.5) changes when it is completely immersed in:
i) Water (Refractive Index 1.33)
ii) A liquid (Refractive index 1.65)


a) Given,

straight n presubscript straight a subscript straight g space equals space 1.56
angle straight A space equals space 60 to the power of straight o [ because it is a regular glass prism]
Using Snell's Law, at the face AC,

sin r2fraction numerator 1 over denominator straight n presubscript straight a subscript straight g end fraction equals fraction numerator 1 over denominator 1.56 end fraction
r2 = sin-1(1/1.56)

r2 = sin-1 (1/1.56)
i.e., r2 = 39.86o

Now,


r1 + r2 = A
r1 = 60o - 39.86o
r1 = 20.14o
Again, using snell's law, we have

straight n presubscript straight a subscript straight g space equals space fraction numerator sin space straight i over denominator sin space straight r end fraction
1.56 space equals space fraction numerator sin space straight i over denominator sin space straight r subscript 1 end fraction
rightwards double arrow space sin space straight i space equals space 1.56 space straight x space sin space straight r subscript 1
space space space space space space space space space space space space space space equals space 1.56 space straight x space sin space left parenthesis 20.14 to the power of straight o right parenthesis
space space space space space space space space space space space space space space equals space 1.56 space straight x space 0.34
space space space space space space space space space space space space space space equals space 0.5304
straight i space equals space sin to the power of negative 1 end exponent space left parenthesis 0.5304 right parenthesis
straight i space equals space 32.03 to the power of straight o

b) i) Given,

Refractive index of glass lens (straight n presubscript straight a subscript straight g right parenthesis = 1.5
Refractive index of water (straight n presubscript straight a subscript straight w) = 1.33
Therefore,
 straight n presubscript straight w subscript straight g space equals space fraction numerator straight n presubscript straight a subscript straight g over denominator straight n presubscript straight a subscript straight w end fraction
straight n presubscript straight a subscript straight g space greater than straight n presubscript straight a subscript straight w
straight n presubscript straight w subscript straight g space less than space straight n presubscript straight a subscript straight g

If the focal length of the lens in air be fa and that in water be fw, then
1 over straight f subscript straight a space equals space left parenthesis n presubscript a subscript g minus 1 right parenthesis open square brackets 1 over R subscript 1 minus 1 over R subscript 2 close square brackets
1 over straight f subscript straight w space equals space left parenthesis n presubscript straight w subscript g minus 1 right parenthesis open square brackets 1 over R subscript 1 minus 1 over R subscript 2 close square brackets
straight f subscript straight w over straight f subscript straight a space equals space fraction numerator space left parenthesis n presubscript a subscript g minus 1 right parenthesis over denominator space left parenthesis n presubscript straight w subscript g minus 1 right parenthesis end fraction greater than space 1
straight f subscript straight w space greater than space straight f subscript straight a
Thus, if the glass lens is immersed in water, then the focal length of the lens increases.

ii) Given: straight n presubscript straight a subscript straight g equals 1.5 comma space straight n presubscript straight a subscript straight l space equals space 1.65
So,
 straight n presubscript straight l subscript straight g space equals space fraction numerator straight n presubscript straight a subscript straight g over denominator straight n presubscript straight a subscript straight l end fraction
straight n presubscript straight a subscript straight l space greater than space straight n presubscript straight a subscript straight g space left parenthesis given right parenthesis
straight n presubscript straight l subscript straight g space equals space fraction numerator straight n presubscript straight a subscript straight g over denominator straight n presubscript straight a subscript straight l end fraction space less than space 1
In this case, we have

1 over straight f subscript straight l equals open parentheses n presubscript l subscript g minus 1 close parentheses open square brackets 1 over R subscript 1 minus 1 over R subscript 2 close square brackets
Therefore, the focal length of the lens in the liquid become negative. Hence, the lens which was convex will behave as concave lens in air.

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