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JEE Chemistry Solved Question Paper 2008

Multiple Choice Questions

An isobar of ₂₀C⁴⁰ is

₁₈Ar⁴⁰
₂₀Ca³⁸
₂₀Ca⁴²
₁₈Ar³⁸

In successive emission of $α$ -and $β$ -particles, the number of $α$ -and $β$ -particles should be emitted for the conversion of ₉₂U²³⁸ to ₈₂P²⁰⁶ are

$7 α, 5 β$
$6 α, 4 β$
$4 α, 3 β$
$8 α, 6 β$

Cell reaction is spontaneous, when

$E_{red}^{°} is negative$
$E_{red}^{°} is positive$
$∆ G ° is negative$
$∆ G ° is positive$

If $∆ E$ is the heat of reaction for

$C_{2} H_{5} OH (l) + 3 O_{2} (g) \to 2 {CO}_{2} (g) + 3 H_{2} O (l) at constant volume, the ∆ H$ (heat of reaction at constant pressure), at constant temperature is

$∆ H = ∆ E + RT$
$∆ H = ∆ E - RT$
$∆ H = ∆ E - 2 RT$
$∆ H = ∆ E + 2 RT$

Which one of the following species acts as both Bronsted acid and base?

$H_{2} {PO}_{2}^{-}$
${HPO}_{3}^{2 -}$
${HPO}_{4}^{2 -}$
All of these

6.
$If C (s) + O_{2} (g) \to CO (g); ∆ H = r and CO (g) + \frac{1}{2} O_{2} (g) \to {CO}_{2} (g); ∆ H = s then, the heat of formation of CO is$

r+s

r-s

s-r

rs

r-s

$C (s) + O_{2} (g) \to CO (g); ∆ H = r . . . (i) CO (g) + \frac{1}{2} O_{2} (g) \to {CO}_{2} (g); ∆ H = s . . . . . (ii) CO (g) + \frac{1}{2} O_{2} (g) \to {CO}_{2} (g); ∆ H = ? Subtract eq . (ii) from eq . (i) C (s) + O_{2} (g) \to CO (g); ∆ H = r . . . (i) CO (g) + \frac{1}{2} O_{2} (g) \to {CO}_{2} (g); ∆ H = s . . . . . (ii) - - - - after subtract we get, C (s) + \frac{1}{2} O_{2} (g) \to CO (g); ∆ H = r - s$