Subject

Chemistry

Class

JEE Class 12

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JEE Chemistry Solved Question Paper 2009

Multiple Choice Questions

The correct statement with regard to $H_{2}^{+} and H_{2}^{-}$ is

both $H_{2}^{+} and H_{2}^{-}$ are equally stable
both $H_{2}^{+} and H_{2}^{-}$ do not exist
H $_{2}^{-}$ is more stable than H $_{2}^{+}$
H $_{2}^{+}$ is more stable than H $_{2}^{-}$

Arrange the following in the increasing order of their bond order

O₂, O $_{2}^{+}, O_{2}^{-} and O_{2}^{2 -}$

$O_{2}^{2 -}, O_{2}^{-}, O_{2}, O_{2}^{+}$
$O_{2}^{2 -}, O_{2}^{-}, O_{2}^{+}, O_{2}$
$O_{2}^{+}, O_{2}, O_{2}^{-}, O_{2}^{2 -}$
$O_{2}, O_{2}^{+}, O_{2}^{-}, O_{2}^{2 -}$

30 cc of $\frac{M}{3}$ , 20 cc of $\frac{M}{2}$ HNO₃ and 40 cc of $\frac{M}{4}$ NaOH solutions are mixed and the volume was made up to 1 dm³. The pH of the resulting solution is

10^-6 M NaOH is diluted 100 times. The pH of the diluted base is

between 7 and 8
between 5 and 6
between 6 and 7
between 10 and 11

For the reaction H₂O (l) $⇌$ H₂O (g) at 373 K and 1 atm pressure

$∆$ H = 0
$∆$ E = 0
$∆ H = T ∆ S$
$∆ H = ∆ E$

The correct set of four quantum numbers for outermost electron of potassium (Z = 19) is

4, 1, 0, $\frac{1}{2}$
3, 1, 0, $\frac{1}{2}$
4, 0, 0, $\frac{1}{2}$
3, 0, 0, $\frac{1}{2}$

A body of mass x kg is moving with a velocity of 100 ms^-1. Its de-Broglie wavelength is 6.62 × 10^-35 m. Hence, x is (h = 6.62 × 10^-34Js)

0.1 kg
0.25 kg
0.15 kg
0.2 kg

8.
The correct order of ionisation energy of C, N, O, F is

F < O < N < C

F < N < C < O

C < N < O < F

C < O < N < F

C < O < N < F

Ionisation energy generally increases from left to right in a period but ionisation energy of nitrogen is greater than oxygen due to stable p³ configuration. Hence, the correct order is as-

C < O < N < F