The number of molecules of CO2 liberated by the complete combusti

Subject

Chemistry

Class

JEE Class 12

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 Multiple Choice QuestionsMultiple Choice Questions

1.

If the equilibrium constant for the reaction,

H2(g)+ I2(g)  2HI (g) is K. what is the equilibrium constant of HI(g)  12H2(g) +12I2(g) ?

 

  • 1/K

  • √K

  • K

  • 1/√K


2.

The pH of 0.01 M solution of acetic acid is 5.0. What are the values of [H+] and Ka respectively?

  • 1 × 10-5M, 1× 10-8

  • 1 × 10-5M, 1× 10-9

  • 1 × 10-4M, 1 × 10-8

  • 1 × 10-3M, 1 × 10-8


3.

A system is provided with 50 J of heat and the work done on the system is 10 J. What is the change in internal energy of the system in Joules?

  • 60

  • 40

  • 50

  • 10


4.

Which one of the following transitions of an electron in hydrogen atom emits radiation of the lowest wavelength?

  • n2 = ∞ to n1=2

  • n2= 4 to n1 =3

  • n2= 2 to n1 =1

  • n2 = 5 to n1=3


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5.

Which one of the following conditions is incorrect for a well behaved wave function (Ψ)?

  • Ψ must be fine

  • Ψ must be single valued

  • Ψ must be infinite

  • Ψ must be continuous


6.

The electron affinity values of elements A, B, C and D are respectively -135, -60, -200 and -348 kJ mol-1. The outer electronic configuration of element B is

  • 3s2 3p5

  • 3s3p4

  • 3s2 3p3

  • 3s2 3p2


7.

Match the following
  Column I (molecules)   Column II ( number of lone pair on central atom)
A NH3 1 Three
B H2O 2 Two
C XeF2 3 Zero
D CH4 4 Four
    5 One

  • A B C D

    5 1 3 2

  • A B C D

    3 1 2 5

  • A B C D

    5 1 2 3

  • A B C D

    1 5 3 4


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8.

The number of molecules of CO2 liberated by the complete combustion of 0.1 g atom of graphite in air is

  • 3.01 × 1022

  • 6.02 × 1023

  • 6.02 × 1022

  • 3.01 × 1023


C.

6.02 × 1022

C(s) 1mol+ O2(g)   CO2(g)1mol = 6.023 ×1023 1 mole of graphite on complete combustion gives CO2    = 6.023 × 1023 molecules. 0.1 moles of graphite will give CO2  = 6.023 × 1023 ×0.11 =6.023 × 1022


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9.

CH4 diffuses two times faster than a gas X. The number of molecules present in 32 g ofgas X is (N is Avogadro number)

  • N

  • N/2

  • N/4

  • N/16


10.

The orange coloured compound formed when H2O2 is added to TiO2 solution acidified with conc. H2SO4 is

  • Ti2O3

  • H2Ti2O8

  • H2TiO3

  • H2TiO4


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