Heat of neutralization of HCl and NaOH is
-13.7 kcal
-13.7 J
-13.7 kJ
None of these
A.
-13.7 kcal
The heat of neutralisation of a strong acid (HCl) and a strong base (NaOH) is always -13.7 kcal or -57.5 kJ.
NO is detected by ring test. Ring formed has formula
FeSO4.HNO2
FeSO4.NO2
[Fe(H2O)5.NO]2+
Fe(OH)2.NO
The process of oxidation involve
loss of electron
gain of electron
loss of proton
loss of neutron
The IUPAC name of the following compound
CH3 - CH = CH - C ≡ CH is
pent-2-en-4-yne
pent-1-en-4-yne
pent-3-en-1-yne
pent-2-en-5-yne
The number of electrons transferred when KMnO4 acts as an oxidising agent to give MnO2 and Mn2+ respectively are
2, 3
1, 5
3, 5
1, 3