For the equilibrium,CaCO3 (s) ⇌ CaO (s) + CO2 (g)

Subject

Chemistry

Class

JEE Class 12

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 Multiple Choice QuestionsMultiple Choice Questions

1.

The statement that is not correct is

  • A furnace filled with haemalite is used to convert cast iron to wrought iron

  • Collectors enhance the wettability of mineral particles during froth flotation

  • In vapour phase refining, metal should form a volatile compound

  • Copper from its low grade ores is extracted by hydrometallurgy


2.

For Cr2O72- + 14 H+ + 6e- → 2Cr3+ + 7H2O; E° = 1.33 V. At [Cr2O72-] = 4.5 millimole, [Cr3+] = 15 millimole, E is 1.067 V. The pH of the solution is nearly equal to

  • 2

  • 3

  • 5

  • 4


3.

1.78 g of an optically active L-amino acid (A) is treated with NaNO3/ HCl at 0°C. 448 cm3 of nitrogen was at STP is evolved. A sample of protein has 0.25% of this amino acid by mass. The molar mass of the protein is

  • 36500 g mol-1

  • 34500 g mol-1

  • 35400 g mol-1

  • 35600 g mol-1


4.

10 g of a mixture of BaO and CaO requires 100 cm3 of 2.5 M HCl to react completely. The percentage of calcium oxide in the mixture is approximately (Given: molar mass of BaO = 158)

  • 52.6

  • 55.1

  • 44.9

  • 47.4


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5.

The ratio of heats liberated at 298 K from the combustion of one kg of coke and by burning water gas obtained from kg of coke is (Assume coke to be 100% carbon). (Given : enthalpies of combustion of CO2, CO and H2 as 393.5 kJ, 285 kJ, 285 kJ respectively all at 298 K)

  • 0.79 : 1

  • 0.69 : 1

  • 0.86 : 1

  • 0.96 : 1


6.

Impure copper containing Fe, Au, Ag as impurities is electrolytically refined. A current of 140 A for 482.5 s decreased the mass of the anode by 22.26 g and increased the mass of cathode by 22.011 g. Percentage of iron in impure copper is (Given molar mass Fe = 55.5 g mol-1, molar mass Cu = 63.54 g mol-1)

  • 0.95

  • 0.85

  • 0.96=7

  • 0.90


7.

25 cm3 of oxalic acid completely neutralised 0.064 g of sodium hydroxide. Molarity of the oxalic acid solution is

  • 0.064

  • 0.045

  • 0.015

  • 0.032


8.

The statement that is not correct is

  • Angular quantum number signifies the shape of the orbital

  • Energies of stationary states in hydrogen like atoms is inversely proportional to the square of the principal quantum number

  • Total number of nodes for 3s-orbital is three

  • The radius of the first orbit of He is half that of the first orbit of hydrogen atom


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9.

For the equilibrium,

CaCO3 (s)  CaO (s) + CO2 (g) ; 

Kp = 1.64 atm at 1000 K

50 g of CaCO3 in a 10 L closed vessel is heated to 1000 K. Percentage of CaCO3 that remains unreacted at equilibrium is (Given, R = 0.082 L atm K-1 mol-1).

  • 40

  • 50

  • 60

  • 20


C.

60

CaCO3 (s)  CaO (s) + CO2 (g)

KpCO2 = nV RT

 1.64 = n10 × 0.082 × 1000          n = 1.64 × 100.082 × 1000 = 0.2

i.e. Number of moles of CO2 = 0.2

Initially At equilibrium CaCO3 50 gm = 50100 = 0.5 mol0.2 mol  CaO + CO200.2

Therefore, unreacted CaCO3 = 0.5 - 0.2 = 0.3 mol

and % of unreacted CaCO3 =  0.30.5 × 100 = 60%


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10.

Density of carbon monoxide is maximum at

  • 2 atm and 600 K

  • 0.5 atm and 273 K

  • 6 atm and 1092 K

  • 4 atm and 500 K


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