For the following equilibrium, N2O4 ⇌2NO2 in the gaseo

Subject

Chemistry

Class

JEE Class 12

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 Multiple Choice QuestionsMultiple Choice Questions

1.

The solubihty of AgI in NaI solution is less than that in pure water because

  • Agl forms complex with Nal

  • of common ion effect

  • solubility product of AgI less

  • the temperature of the solution decreases


2.

Hydrogen ion concentration in mol/L in a solution of pH = 5.4 will be

  • 3.98 × 108

  • 3.88 × 106

  • 3.68 × 10-6

  • 3.98 × 10-6


3.

XY2 dissociated as XY2(g) XY(g) + Y (g) When the initial pressure of XY2 is 600 mm Hg, the total equilibrium pressure is 800 mm Hg. Calculate K for the reaction assuming that the volume of the system remains unchanged.

  • 50

  • 100

  • 166.6

  • 400.0


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4.

For the following equilibrium, N2O4 2NO2 in the gaseous phase, NO2 is 50% of the total volume when equilibrium is set up. Hence, per cent of dissociation of N2Ois

  • 50%

  • 25%

  • 66.66%

  • 33.33%


D.

33.33%

N2O4  2NO21                  0(1-x)          2xTotal moles=2x + (1- x) (1 + x)% of NO2 by volume = 2x(1+x)× 100= 500or x=13= 0.33Hence per cent of dissociation of N2O4 33.33%


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5.

Of the given anions, the strongest Bronsted base is

  • ClO-

  • ClO3-

  • ClO2-

  • ClO4-


6.

Which of the following will violate Pauli's exclusion principle?

  • Both (a) and (b)

  • None of the above


7.

The bond order of H2- ion is 12. If it has 2 bonding electron, how many antibonding electrons it will have?

  • 4

  • 3

  • 2

  • 1


8.

Ni2+ ion (Z= 28) contains unpaired electrons

  • 1

  • 2

  • 3

  • 5


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9.

The bond angle is maximum in PI3,which is

Iodide PI3 AsI3 SbI3
Bond angle 102 100°2' 99°
  • due to small size of P

  • due to more bp-bp repulsion in PI3

  • due to less electronegativity of P

  • None of the above


10.

The radius of H-atom in its ground state is 0.58Å .The radius of, 3Li2+ ithe similar state is

  • 0.1777 Å

  • 0.706 Å

  • 1.06 Å

  • 0.058 Å


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