If the given four electronic configurations,(i) n = 4, l = 1(ii)

Subject

Chemistry

Class

JEE Class 12

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 Multiple Choice QuestionsMultiple Choice Questions

1.

For same mass of two different ideal gases of molecular weights M1 and M2, Plots of log V vs log p at a given constant temperature are shown. Identify the correct option.

  • M1 > M2

  • M1 = M2

  • M1 < M2

  • Can be predicted only if temeperature is known


2.

Which of the following has the dimension if [ML0T-2]?

  • Coefficient of viscosity

  • Surface tension

  • Vapour pressure

  • Kinetic energy


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3.

If the given four electronic configurations,

(i) n = 4, l = 1

(ii) n = 4, l = 0

(iii) n = 3, l = 2

(iv) n = 3, l = 1

are arranged in order of increasing energy, then the order will be

  • (iv) < (ii) < (iii) < (i)

  • (ii) < (iv) < (i) < (iii)

  • (i) < (iii) < (ii) < (iv)

  • (iii) < (i) < (iv) < (ii)


A.

(iv) < (ii) < (iii) < (i)

According to (n + l) rule;

(a) More be the sum of (n+l) value, more be the energy

(b) For same value of sum, more be the value of n, more be the energy.

For

(i) n + l → 4 + 1 = 5

(ii) n + l → 4 + 0 = 4

(iii) n + l → 3 + 2 = 5

(iv) n + l → 3 + 1 = 4

Hence, order of energy will be

(iv) < (ii) < (iii) < (i)


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4.

Which of the following sets of quantum numbers represents the 19th electron of Cr(Z = 24)?

  • (4, 1, -1, +12)

  • (4, 0, 0, +12)

  • (3, 2, 0, -12)

  • (3, 2, -2, +12)


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5.

0.126 g of an acid is needed to completely neutralise 20 mL 0.1 (N) NaOH solution. The equivalent weight of the acid is

  • 53

  • 40

  • 45

  • 63


6.

In a flask, the weight ratio of CH4 (g) and SO2 (g) at 298K and 1 bar is 1 : 2. The ratio of the number of molecules of SO2 (g) and CH4 (g) is

  • 1 : 4

  • 4 : 1

  • 1 : 2

  • 2 : 1


7.

C6H5F18 is a F18  radio-isotope labelled organic compound. F18 decays by positron emission. The product resulting on decay is 

  • C6H5O18

  • C6H5Ar19

  • B12C5H5F

  • C6H5O16


8.

Dissolving NaCN in de-ionised water will result in a solution having

  • pH < 7

  • pH = 7

  • pOH = 7

  • pH > 7


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9.

Among Me3N, C5H5N and MeCN (Me = methyl group) the electronegativity of N is in the order

  • MeCN > C5H5N > Me3N

  • C5H5N > Me3N > MeCN

  • Me3N > MeCN > C5H5N

  • Electronegativity same in all


10.

The shape of XeF5- will be

  • square pyramid

  • trigonal bipyramidal

  • planar

  • pentagonal bipyramid


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